I'm not understanding the squeeze theorem. O Lumen OHM2-2-example-04.gif (88 x6 2-3-ex-10-alt.gif (857x| Simplify tan(x)cos(x) | MM. Limit Laws explained ww Squeeze theorem - Wik x+A https://ohm.lumenlearning.com/assess2/?cid=50238&aid=3647337#/skip/14I Apps M McGraw-Hill Conne.E Program: Chemistry. P Employee Self-Servi. Q Lumen OHMCourses in Chemist...FIrst hote that we ca not use1lim x sin1lim z4. lim sinbecause the limit as x approaches 0 of sin1does not exist (see this example 2). Instead we apply1the Squeeze Theorem, and so we need to find a function f smaller than g(x)= x' sinand afunction h bigger than g such that both f(x) and h(x) approach 0. To do this we use ourknowledge of the sine function. Because the sine of any number lies between -1and1o, we can write1< sin-1Any inequality remains true when multiplied by a positive number. We know that a* > 0 for all æand so, multiplying each side of inequalities of æ*, we getsinas illustrated by the figure. We know thatlim x*and lim1Taking f(x) = – a*, g(æ)= x* sin –, and h(x) = x* in the Squeeze Theorem, we obtainlim a* sin1= 0.4:37 PMP Type here to search99+2/14/2021近

Name: I'm not understanding the squeeze theorem. O Lumen OHM2-2-example-04.g
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Description: I'm not understanding the squeeze theorem. O Lumen OHM2-2-example-04.gif (88 x6 2-3-ex-10-alt.gif (857x| Simplify tan(x)cos(x) | MM. Limit Laws explained ww Squeeze theorem - Wik x+A https://ohm.lumenlearning.com/assess2/?cid=50238&aid=3647337#/skip/