Campbell Biology in Focus
3rd Edition
ISBN: 9780134710679
Author: Lisa A. Urry, Michael L. Cain, Steven A. Wasserman, Peter V. Minorsky, Rebecca Orr
Publisher: PEARSON
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Chapter 11.1, Problem 1CC
DRAW IT Pea plants heterozygous for flower position and stem length (Aa Tt) are allowed to self-pollinate, and 400 of the resulting seeds are planted. Draw a Punnett square for this cross. How many offspring would be predicted to have terminal flowers and be dwarf? (See Table 11.1)
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DRAW IT Pea plants heterozygousfor flower position and stem length(AaTt) are allowed to self-pollinate,and 400 of the resulting seeds areplanted. Draw a Punnett square forthis cross. How many offspring wouldbe predicted to have terminal flowers and be dwarf? (See Table 14.1.)
Y = yellow, y = green; R = round seed, r = wrinkled seed
Dihybrid cross:
If you mate YyRr x YyRr then what proportion of offspring will be green and wrinkled?
6/16
3/16
O 1/16
O 9/16
Let P = purple flowers and p = white, and T = tall plants and t = dwarf. What are the genotypes of the gametes that are
produced by a plant that is heterozygous for both traits? hint* This is a dihybrid self cross of an F1 heterozygous
generation.
O Tt, TT, tt, Pp, PP, and pp
P, p, T, and t
PT, Pt, pT, and pt
PT and pt
Chapter 11 Solutions
Campbell Biology in Focus
Ch. 11.1 - DRAW IT Pea plants heterozygous for flower...Ch. 11.1 - List all gametes that could be made by a pea plant...Ch. 11.1 - Prob. 3CCCh. 11.2 - For any gene with a dominant allele A and...Ch. 11.2 - Two organisms, with genotypes BbDD and BBDd, are...Ch. 11.2 - Prob. 3CCCh. 11.3 - Incomplete dominance and epistasis are both terms...Ch. 11.3 - Prob. 2CCCh. 11.3 - WHAT IF? A rooster with gray feathers and a hen of...Ch. 11.4 - Lucia and Jared each have a sibling with cystic...
Ch. 11.4 - MAKE CONNECTIONS In Table 11.1, note the...Ch. 11 - DRAW IT Two pea plants heterozygous for the...Ch. 11 - A man with type A blood marries a woman with type...Ch. 11 - A man has six fingers on each hand and six toes on...Ch. 11 - Prob. 4TYUCh. 11 - Flower position, stem length, and seed shape are...Ch. 11 - Prob. 6TYUCh. 11 - Prob. 7TYUCh. 11 - Prob. 8TYUCh. 11 - Prob. 9TYUCh. 11 - Prob. 10TYUCh. 11 - In tigers, a recessive allele that is pleiotropic...Ch. 11 - Prob. 12TYUCh. 11 - Prob. 13TYUCh. 11 - Imagine that you are a genetic counselor, and a...Ch. 11 - Prob. 15TYUCh. 11 - Prob. 16TYUCh. 11 - Prob. 17TYUCh. 11 - Prob. 18TYU
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- A Heterozygous plant, GgHhliJjKk is allowed to self-fertilize. What is the probability that an offspring will be GgHHliJjKk?arrow_forwardPurple Stem A All seedlings are 72 hours old. Standard Height R seed coat Green Stem a Purple Stem Standard Non-Purple Stem Standard (anl/anl, ROS/ROS) Purple Stem Rosette-Dwarf Non-Purple Stem Rosette-Dwarf Dwarf Height r (ANLIANL, ROS/ROS) (ANLIANL, ros/ros) (anl/anl, ros/ros) Cross a heterozygous (for color only!) purple stem standard (homozygous for height) with a green stem dwarf. What are the parental genotypes? What % is each phenotype in the offspring?arrow_forwardA heterozygous plant with genotype Aa self-pollinates. Find the probability that an offspring is tall for the following genetic systems. Half of heterozygous plants and one fourth of homozygous plants are tall (it depends on their position in the greenhouse)arrow_forward
- Character Seed Shape Round (R) Wrinkled (r) Seed Color Yellow (Y) Green (y) Pod Shape Inflated (I) Constricted (i) If a plant that is heterozygous for all theses characters is crossed with a plant homozygous dominant for seed shape and seed color and heterozygous for pod shape, what proportion of the offspring would you expect to be as follows: 1. Homozygous dominant for the three characters. (Answer in fraction) ____ 2. Recessive for the three characters. (Answer in fraction) _________ 3. Heterozygous dominant for the three characters. Answer in fraction) _______arrow_forwardSmooth seed shape is dominant to wrinkled. The F2 generation is as follows: 3/4 smooth: 1/4 wrinkled. What is the expected F1 genotypic ratio?arrow_forwardIdentify the genotypes of the pea flower plants for each generation P (Guadretieding parents) Phenotypes Purple flowers : Genotypes White flowers 1 2 F1 Gerleyatids) Phenotypes All purple flowers : Genotypes 3 Self- or cross-pollination F2 Generation Phenotypes Purple flowers : Genotypes White flowers 4arrow_forward
- You are planting a cherry orchard with two rows of female fruiting trees. Below is a diagram of their location, and three empty plots where you could plant male pollen trees. Left Plot S₁S₁ Left S₁ S₂ Middle Middle Plot S₁S3 Middle S₂S3 S₂S3 S₂S3 Based on the S genotype of the above female trees, where would you place male pollen trees with the following genotypes to maximise fertilisation? S₂S₂ Middle S₂S3 Right to S3 S3 Middle = S₁S₁ S₁S₁ S₁S₁ Right Plotarrow_forwardSuppose a purple flower heterozygous for stem size is crossed with a large stem (dominant) purple flower. What are the possible genotypes and phenotypes of offspring?arrow_forwardGreen leaves are dominant to red. Long petals are dominant to short. Cross a homozygous green, heterozygous long and a homozygous red, homozygous long. Give phenotypic ratio and show Punnett square.arrow_forward
- Round seed is dominant over wrinkled. Yellow cotyledon is dominant overgreen. Full pod is dominant over constricted. The genes for these traits arefound on separate chromosomes. If a trihybrid plant is self-fertilized, whatproportion of the progeny will have round seeds in constricted pods?Express answer in fraction form.arrow_forwardMore Crosses with Pea Plants: The Principle of Independent Assortment Consider the following cross: P1: AABBCCDDEE aabbccddee F1: AaBbCcDdEe (self-cross to get F2) What is the chance of getting an AaBBccDdee individual in the F2 generation?arrow_forwardFruit weight is controlled by 4 gene pairs. The homozygous dominant weighs 200 g while the homozygous recessive weighs 80 g. Assume that the alleles have equal contribution and have cumulative effects. The F1 and F2 of the two parents below were studied. Parent 1 - D1D1D2D2D3D3d4d4 x Parent 2 - d1d1d2d2d3d3D4D4 Compute for the contribution of the dominant allele. Compute for the fruit weight of parental 1 and parental 2.arrow_forward
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