Which of the following elements most easily gives up electrons during reactions: Li,K, or Cₛ ? Explain your choice.

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The abbreviated orbital diagram shown below corresponds to which element? [Kr] 4d 5p OSi Ge O Cd O Sn O r O Hg

Explain why sulfur has a larger first ionization energy than silicon.

Place the following elements in order of increasing electron Affinity (larger negative numbers, further from "0") B, O, C, Be

Give the indicated full or noble gas electron configuration Note: you can't do superscripts in questions answers, so format your answer without superscripts but with one space between each orbital. E.g. Li would be 1s2 2s1 instead of 1s22s The number in parentheses after the symbol is the element's atomic number. Full configuration: N (7) Full configuration: Si (14) Full configuration: Ti (22) Noble gas configuration: Ba (56) ( Noble gas configuration: Te (52) (99+ hp

Imagine a universe where there are three spin states for the electron instead of two (for example, spin up, spin down, and spin cray-cray). The number of subshells per shell and number of orbitals per subshell stay the same, but an orbital now holds three electrons instead of two. The names of the elements stay the same. Draw the top three rows of what this new periodic table would look like, indicating which elements are in which groups in our new universe, and show the electron configurations of each of the elements of these three rows.

Select the statement(s) that explain(s) the relationship between the arrangement of elements by size and first ionization energy. 1. The first set of paired electrons in a pp subshell experience a large amount of electron-electron repulsion, making the fourth electron in a pp subshell easy to remove. 2. The third unpaired electron in a pp subshell causes a lot of electron-electron repulsion among the orbitals, making the third electron in a pp subshell easy to remove. 3. A pp subshell with only one unpaired electron is extremely stable, making the fifth electron in a pp subshell easy to remove. 4. The two arrangements are the same because IE of elements increases from left to right and the radii of elements decreases from left to right. 5. A full ss subshell is able to shield a newly filled pp subshell from the nucleus, making the first electron in a pp subshell easy to remove.