
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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Can carbon dioxide be liquefied at room temperature (20ºC)? If so, how? If not, why not?
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- HW1. Due: 02/08/2024. 1. The density of dry air at p = 1.0 bar and T =300 K is 1.161 kg/m³. Assuming it consists entirely of N₂ and O₂ and using the ideal gas law, determine the amount of each gas in moles in a volume of 1 m³ and their mole fractions. 2. (a) Calculate the amount of gas in moles per cubic meter of atmosphere at p = 1 atm and T = 298 K using the ideal gas equation. (b) The atmospheric content of CO₂ is about 360 ppmv (parts per million by volume). Assuming a pressure of 1.00 atm, estimate the amount of CO₂ in a 10.0 km layer of the atmosphere at the surface of the earth. The radius of the earth is 6370 km. (The actual amount of CO₂ in the atmosphere is about 6.0 x 1015 mol.) 3. The van der Waals parameter b is a measure of the volume excluded due to the finite size of the molecules. Estimate the size of a single molecule from the data given below. STATES OF MATTER AND THE VAN DER WAALS EQUATION Table 1.1 Van der Waals constants a and b and critical constants T.. p, and V…arrow_forwardThe recommended daily caloric intake is 2000 calories (8,400,000J). This is because this is the same value for how much the average body loses to heat and work in a typical day (your change in energy is zero because you take in the same amount of energy you lose). A) If you lose a total of 8,400,000J (Qout+W=total lost), but consume 1200 calories of food (5,000,000J), what would your change in energy be? B) Assuming your change in energy is negative (hint-it should be), where does your body get the extra energy to maintain it's temperature?arrow_forwardSuppose we have a piece of a candy bar that has an initial mass of 28g. If we ignite the piece of candy bar (literally burn it), and it increases the temperature of 341.42g of water from 18.11°C to 69.72°C, how many calories per gram of energy did the candy bar provide if the final mass of the marshmallow is 3.92? Note: 1.00 cal = 4.184 J. Give your answer in units of cal/g.arrow_forward
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