Chapter 11, Problem 11.148QP

Interpretation Introduction

Interpretation:

The percent composition by volume of the mixture has to be calculated.

Concept introduction:

We start with Graham’s law as this problem relates to effusion of gases. Using Graham’s Law, we can calculate the effective molar mass of the mixture of ${\text{CO and CO}}_{\text{2}}$. Once the effective molar mass of the mixture is known, we can determine the mole fraction of each component.  $\text{Because nαV at constant T and P, the volume fraction = mole fraction}$ .

$\begin{array}{l}\frac{{\text{r}}_{\text{He}}}{{\text{r}}_{\text{mix}}}\text{=}\sqrt{\frac{{\text{M}}_{\text{mix}}}{{\text{M}}_{\text{He}}}}\\ \\ {\text{M}}_{\text{mix}}\text{=}{\left(\frac{{\text{r}}_{\text{He}}}{{\text{r}}_{\text{mix}}}\right)}^{\text{2}}{\text{M}}_{\text{He}}\end{array}$