Physical Universe
16th Edition
ISBN: 9780077862619
Author: KRAUSKOPF, Konrad B. (konrad Bates), Beiser, Arthur
Publisher: Mcgraw-hill Education,
expand_more
expand_more
format_list_bulleted
Question
Chapter 10, Problem 19E
(a)
To determine
The characteristic about the outer electron shells in alkali metals.
(b)
To determine
To Explain:
The characteristic about the outer electron shells in halogens.
(c)
To determine
The characteristic about the outer electron shells in inert gases.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
(50/100) 2. When a phosphorus atom is substituted for a silicon atom in a crystal, four of the phosphorus
valence electrons form bonds with neighboring atoms and the remaining electron is much more loosely bound.
You can model the electron as free to move through the crystal lattice. The phosphorus nucleus has one more
positive charge than does the silicon nucleus, however, so the extra electron provided by the phosphorus atom
is attracted to this single nuclear charge +e. The energy levels of the extra electron are similar to those of the
electron in the Bohr hydrogen atom with two important exceptions. First, the Coulomb attraction between the
electron and the positive charge on the phosphorus nucleus is reduced by a factor of 1/k from what it would be
in free space, where k is the dielectric constant of the crystal. As a result, the orbit radii are greatly increased
over those of the hydrogen atom. Second, the influence of the periodic electric potential of the lattice causes the…
Question:
"In the atomic structure, electrons reside in different energy levels around the nucleus. According to the Pauli Exclusion Principle, no two electrons in a single atom can have the same set of quantum numbers. Considering a neutral atom of silicon (Si) with an atomic number of 14, how many electrons can it accommodate in its third principal energy level (n=3), and why?"
An atom that is considered a "good" electron needs to have an available energy level that is lower than the energy of a valence electron of a different atom. An atom that is considered a "poor" electron will have the valence electrons be at a higher energy than other atoms. Given this, consider rows 2 and 5 in the periodic table. Why should fluorine, in row 2, be more reactive than iodine, in row 5, while lithium, in row 2, is less reactive than rubidium, in row 5?
Chapter 10 Solutions
Physical Universe
Ch. 10 - Prob. 1MCCh. 10 - Prob. 2MCCh. 10 - Prob. 3MCCh. 10 - Prob. 4MCCh. 10 - Prob. 5MCCh. 10 - Prob. 6MCCh. 10 - Prob. 7MCCh. 10 - Prob. 8MCCh. 10 - Prob. 9MCCh. 10 - Prob. 10MC
Ch. 10 - Prob. 11MCCh. 10 - Prob. 12MCCh. 10 - Prob. 13MCCh. 10 - Prob. 14MCCh. 10 - Prob. 15MCCh. 10 - Prob. 16MCCh. 10 - Prob. 17MCCh. 10 - Prob. 18MCCh. 10 - Prob. 19MCCh. 10 - Prob. 20MCCh. 10 - Prob. 21MCCh. 10 - Prob. 22MCCh. 10 - Prob. 23MCCh. 10 - Prob. 24MCCh. 10 - Prob. 25MCCh. 10 - Prob. 26MCCh. 10 - Prob. 27MCCh. 10 - Prob. 28MCCh. 10 - Prob. 29MCCh. 10 - Prob. 30MCCh. 10 - Prob. 31MCCh. 10 - Prob. 32MCCh. 10 - Prob. 33MCCh. 10 - Prob. 34MCCh. 10 - Prob. 35MCCh. 10 - Prob. 36MCCh. 10 - Prob. 37MCCh. 10 - Prob. 38MCCh. 10 - Prob. 39MCCh. 10 - Prob. 40MCCh. 10 - Prob. 1ECh. 10 - Prob. 2ECh. 10 - Prob. 3ECh. 10 - Prob. 4ECh. 10 - Prob. 5ECh. 10 - Prob. 6ECh. 10 - Prob. 7ECh. 10 - Prob. 8ECh. 10 - Prob. 9ECh. 10 - Prob. 10ECh. 10 - Prob. 11ECh. 10 - The Bronze Age got its name from the ability of...Ch. 10 - Prob. 13ECh. 10 - What energy change would you expect when a...Ch. 10 - Prob. 15ECh. 10 - Prob. 16ECh. 10 - Prob. 17ECh. 10 - Prob. 18ECh. 10 - Prob. 19ECh. 10 - Prob. 20ECh. 10 - Prob. 21ECh. 10 - Prob. 22ECh. 10 - Prob. 23ECh. 10 - Prob. 24ECh. 10 - Prob. 25ECh. 10 - Prob. 26ECh. 10 - Prob. 27ECh. 10 - Prob. 28ECh. 10 - Prob. 29ECh. 10 - Prob. 30ECh. 10 - Prob. 31ECh. 10 - Prob. 32ECh. 10 - Prob. 33ECh. 10 - Prob. 34ECh. 10 - Prob. 35ECh. 10 - Prob. 36ECh. 10 - Prob. 37ECh. 10 - Prob. 38ECh. 10 - Prob. 39ECh. 10 - Prob. 40ECh. 10 - Prob. 41ECh. 10 - Prob. 42ECh. 10 - Prob. 43ECh. 10 - How many atoms of which elements are present in a...Ch. 10 - Prob. 45ECh. 10 - Prob. 46ECh. 10 - Prob. 47ECh. 10 - Prob. 48ECh. 10 - Prob. 49ECh. 10 - Prob. 50ECh. 10 - Prob. 51ECh. 10 - Prob. 52ECh. 10 - Prob. 53ECh. 10 - Prob. 54ECh. 10 - Prob. 55ECh. 10 - Prob. 56ECh. 10 - Prob. 57ECh. 10 - Prob. 58ECh. 10 - Prob. 59ECh. 10 - Prob. 60ECh. 10 - Prob. 61ECh. 10 - Prob. 62E
Knowledge Booster
Similar questions
- 4) Molybdenum has a BCC crystal structures, the density of molybdenum is 10.22 g/cm³ and its atomic mass is 95.94 g/mol. What are the atomic concentration, the lattice parameter a and the atomic radius of molybdenum. What is the atomic concentration in the primitive cell? 5) Tungsten (W) has the BCC crystal structure. The radius of the W atom is 0.1371 nm. The atomic mass of W is 183.8 amu (g/mol). Calculate the number of W atoms per unit volume and the density of W (NA = 6.02 x 10²3).arrow_forward-5 2 3 Suppose that A and B G.Find AB. %3D \1 3. -1arrow_forwardCan you explain to me how this is solved - If 112 g of silicon (Si) react completely with 64 g of oxygen (O) to form silica (SiO2), what is the atomic weight of silicon? I am supposed to solve it not using a periodic table and am very confused as to how to get to the answer in the book, 28.arrow_forward
- What fraction of the total volume of an iceberg is exposed above the surface of the ocean? DATA for the densities of sea ice and water: Use these values to 4 significant figures: 919.0 kg/m^3 and 1033 kg/m^3 A: 0.0469 OB: 0.0530 OC: 0.0599 OD: 0.0677 OE: 0.0765 OF: 0.0864 OG: 0.0977 OH: 0.1104arrow_forward4. Liner ionic crystal. Consider a line of 2N ions of alternating charge ±q with a repulsive potential energy A/R" between nearest neighbors. (a) Show that at the equilibrium separation (CGS) (b) Let the crystal be compressed so that R. → R. (1-8). Show that the work done in a compressing a unit length of the crystal has the leading term C8²/2, where 2 (n-1)q² In 2 (CGS) C = U(R): = 2Nq² In 2 (₁-1). Ro n Ro To obtain the results in SI, replace q² by q²/4л. Note: We should not expect to obtain this result from the expression for U(R), but we must use the complete expression for U(R).arrow_forwardPlease give a detailed explanation. The answer is sqrt(3/(4pi)).arrow_forward
- The mass of the most common silicon atom is 4.646 * 10-26 kg, and the mass of the most common oxygen atom is 2.656 * 10-26 kg. When a molecule of silicon monoxide (SiO) makes a transition between the l = 1 and l = 0 rotational levels, it emits a photon of wavelength 6.882 mm. Find the distance between the Si and O nuclei.arrow_forward2.1. A neutral atom has the following electronic configuration: 1s? 2s² 2p° 3s² 3p³ (a). How many electrons are in the M shell? (b). How many protons are in the atomic nucleus? (c). To which group of the periodic table does this element belong?arrow_forwardCalculate the binding energy between the FCC elements below: ELEMENT A: lonic charge= 1 Weight = 43.36 g/mol %3D radius = 291 pm %3D Atomic number = 98 %3D ELEMENT B: lonic charge = -1 Weight = 216.89 g/mol %3D radius = 280 pm Atomic number = 9.3 Answer:arrow_forward
- Table 1.2 Structures and Cell Dimensions of Some Elements and Compounds Element or compound 7803838 2 2 2 2 2 5 Al Be Pt Si Ag Na Structure Agl ZnS CdS fec hcp fcc Diamond bcc hcp fcc Diamond fec bcc fec Diamond fec bcc hep LiH NaCl AgBr MnO CsCl TIBr Cu Zn (B-brass) Cesium chloride CuF Sodium chloride Sodium chloride Sodium chloride Sodium chloride Cesium chloride Cesium chloride Zincblende Zincblende Zincblende Zincblende a, Å 4.04 2.27 5.56 3.56 2.88 2.51 3.61 5.65 4.07 2.86 3.92 5.43 4.08 4.28 2.66 4.08 5.63 5.77 4.43 4.11 3.97 2.94 4.26 6.47 5.41 5.82 c, Å 3.59 4.07 4.94arrow_forwardVIII.(16 ) Three rotational lines spectrum for H Br( atomic mass of Br = 79.9 g/1 were recorded ( in cm") at : 99.90, 116.43 and 132.89. Answer the following: a) what is the value of B in cm" ? b) what is the value of moment of inertia in kgm? c) what is the bond length in Å d) assign these transitionsarrow_forwardIt is relatively easy to strip the outer elections from a heavy atom like that of uranium (which then becomes a uranium ion), but it is very difficult to remove the inner electrons. Why do you suppose this is so?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you