Introductory Chemistry For Today
8th Edition
ISBN: 9781285644561
Author: Seager
Publisher: Cengage
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A titration of vinegar was conducted using 0.756
M NaOH. In total, 30.54 mL of NaOH were
added when the solution turned pink. How many
moles of NaOH were involved in the reaction?
Write your answer in standard notation with the
correct number of significant figures. You do not
need to include units.
TUMS is a popular remedy for acid indigestion. A typical TUMS tablet contains calcium carbonate plus some inert substances. When ingested, it reacts with the gastric juice (hydrochloric acid) in the stomach to give off carbon dioxide gas. When a 1.344−g tablet reacted with 40.00 mL of hydrochloric acid (density = 1.140 g/mL), carbon dioxide gas was given off, and the resulting solution weighed 46.699 g. Calculate the number of liters of carbon dioxide gas released if its density is 1.81 g/L
Decide whether each proposed multiplication or division of measurements is possible. If it is possible, write the result in the last column of the table.
proposed
multiplication or division
Is this
possible?
result
480. mg
O yes
= ?
0.080 g
O no
O yes
(3.0 g) · (0.029 kg) = ?
O no
O yes
(7.0 m) · (6.0 s) = ?
O no
O Ooo
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- A 15.5 g sample of sodium carbonate is added to a solution of acetic acid weighing 19.7 g. The two substances react, releasing carbon dioxide gas to the atmosphere. After reaction, the contents of the reaction vessel weigh 28.7 g. What is the mass of carbon dioxide given off during the reaction?arrow_forward1.87 A solution of ethanol in water has a volume of 54.2 mL and a mass of 49.6 g. what information would you need to look up and how would you determine the percentage of ethanol in this solution?arrow_forward1. A vial with a mixture of sand and salt is placed on an analytical balance. The mass reads 3.4155 g. Some of this mixture is poured out of the vial into a beaker. The vial with the remaining mixture is then placed on the same balance. Its mass now reads 2.8540 g. What was the mass of the sand and salt mixture transferred?arrow_forward
- The composition of a mixture of potassium chlorate and potassium chloride is to be determined. A 9.5 gram sample of the mixture is heated until the creation of oxygen gas stops. If the sample mass after heating is 7.04 grams, what is the percent by mass of potassium chlorate in the mixture? Report your answer with 3 significant figures.arrow_forwardFranklin was performing an experiment by combining hydrochloric acid and sodium hydroxide. He measured the mass of his reactant materials to be 35g. The reaction resulted in the production of salt and water. He reported that his products weighed 32g. Which best describes the results of Franklin’s experiment? No error occurred, some of the products are always lost as heat. An error occurred, the mass of the reactants should equal the mass of the products. An error occurred, the products should weigh more than the reactants. No error occurred, water is not weighed when determining the weight of the products.arrow_forward2. The picture in the introduction shows that the mass of a crucible and lid was determined to be 22.1504 g. The hydrate was placed into the crucible, and now the crucible with lid and hydrate weighed 24.2901 g. The hydrate in the crucible was then heated and all water was removed. Once cooled, the crucible with lid and dried hydrate weighed 23.0063 g. a) Calculate the mass of the hydrate. b) Calculated the mass of water lost. c) Calculate the mass percentage of water in the hydrate. percent (%) composition = of water mass of water lost х 100 mass of entire hydratearrow_forward
- A sunscreen preparation contains 2.50% by mass benzyl salicylate. If a tube contains 4.0 ounces of sunscreen, determine how many kilograms of benzyl salicylate are needed to manufacture 325 tubes of sunscreen. Conversion: 2.205 lb= 1 kg. 16.0 oz = 1 lbarrow_forwardA student dissolved 230.8 grams of cesium chloride in 100.0 grams of 90 °C water. The student then cooled that solution to 20 °C . That cooled solution formed a solid (or "precipitate"), and after separating and drying this solid the student found that the solid weighed 43.8 grams. What is the solubility of cesium chloride in water at 20 °C ? < calculate your answer as grams of cesium chloride per 100 grams of water, but DO NOT include your units in your answer>arrow_forwardBlood alcohol content is a measure of alcohol in the blood as a percentage. It is calculated in grams per 100 mL of blood, so a BAC of 0.08 means your blood is 0.08% alcohol by volume. what is the total mass of alcohol (in grams) that is present for the same adult male whose total blood volume is 5.6L?arrow_forward
- A 15.2-g sample of sodium carbonate is added to a solution of acetic acid weighing 19.4 g. The two substances react, releasing carbon dioxide gas to the atmosphere. After reaction, the contents of the reaction vessel weighs 28.7 g. What is the mass of carbon dioxide given off during the reaction? Mass =arrow_forwardO MEASUREMENT Adding or subtracting and multiplying or dividing measurements A chemistry student must write down in her lab notebook the concentration of a solution of sodium hydroxide. The concentration of a solution equals the mass of what's dissolved divided by the total volume of the solution. Here's how the student prepared the solution: • The label on the graduated cylinder says: empty weight: 1.5 g • She put some solid sodium hydroxide into the graduated cylinder and weighed it. With the sodium hydroxide added, the cylinder weighed 36.669 g. • She added water to the graduated cylinder and dissolved the sodium hydroxide completely. Then she read the total volume of the solution from the markings on the graduated cylinder. The total volume of the solution was 37.11 mL. What concentration should the student write down in her lab notebook? Be sure your answer has the correct number of significant digits. g mL Explanation -1 Check 99+ 0/5 VUDU © 2023 McGraw Hill LLC. All Rights…arrow_forwardYou are making a rubbing alcohol (=isopropyl alcohol) solution to disinfect surfaces. You start with 323.1 mL of a 7.465 M isopropyl alcohol solution, and dilute it with pure water. After the dilution, you end up with a 1.856 M solution. What is the final volume of the solution after the water has been added? Enter your answer in the units of L (liters), do not enter the unit.arrow_forward
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