Introductory Chemistry For Today
8th Edition
ISBN: 9781285644561
Author: Seager
Publisher: Cengage
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2. Do the following calculations and use the correct number of significant figures in your answers. Assume all numbers are the results of measurements.
a. 0.208 + 4.9 + 1.11
b. 228 + 0.999 + 1.02
c. 8.543 − 7.954
d.(3.2 × 10−2) + (5.5 × 10−1) (hint: Write in the decimal form first, then add.)
e. 336.86 − 309.11
f. 21.66 − 0.02387
a. Using the correct rules for multiplication/division and significant figures provide the answer for the following calculation.
6.98 x 89.44 =
b. Using the correct rules for multiplication/division and significant figures provide the answer for the following calculation.
7831 x 76.987 =
c. Using the correct rules for addition/subtraction and significant figures provide the answer for the following calculation.
7831 + 76.987 =
d. Using the correct rules for addition/subtraction and significant figures provide the answer for the following calculation.
7831.67 + 76.987 =
e. Using the correct rules for addition/subtraction and significant figures provide the answer for the following calculation.
7831.67 + 76.987 =
part A: Sort the following numbers according to whether they should be rounded up or down when rounding to the nearest tenth (the first digit after the decimal).
3.1760, 4.319, 19.47, 5.82, 66.9214, 8878.2010, 7.084, 124.76
part B: Drag the answers that have been correctly rounded to the appropriate number of significant figures to their place in the table. To avoid rounding errors, start with the unrounded value before conducting each manipulation.
Drag the appropriate labels to their respective targets.
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14.93
Group 3 14.93
12
Group 1 12
14.92
Group 3 14.92
3.62
Group 4 3.62
14
Group 3 14
3.7
Group 4 3.7
15
Group 3 15
3.6
Group 4 3.6
15.0
Group 3 15.0
3.63
Group 4 3.63
14.9
Group 3 14.9
3.623
Group 4 3.623
12.47
Group 1 12.47
7.97
Group 2 7.97
12.46
Group 1 12.46
7.966
Group 2 7.966
12.4
Group 1 12.4
7.0
Group 2 7.0
13
Group 1 13
7.96
Group 2 7.96
12.5
Group 1 12.5
8.0
Group 2 8.0
3.622
Group 1…
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- How many significant figures are in each measurement? (a) 3.1416 degrees (b) 0.00314 K (c) 1.0079 s (d) 6.022 1023 particlesarrow_forwardIII. Perform these calculations and express the result with the proper number of significant figures. a. (4.850 g – 2.34 g)/1.3 mL b. (4.66 x 10-3) × 4.666 c. 0.003400/65.2arrow_forwardDo the following multiplication and division calculations. Give a final answer with the correct number of significant figures and the correct units. Units can cancel or multiply just like number factors. (2.5 x 103 m/s) x (5.00 x 10-6 s) = ?arrow_forward
- I think I did a calculation wrong but I am having trouble understanding significant figures. In this problem, I am calculation the density of water from my previous calculations mass= 7.359g and volume=7.8mL. So I then divided 7.359g by 7.8mL to find density and got (.9434615385) on my calculator which I then turned into (.94) because I believe there should be 2 significant figures. Is (.94) correct or should 1.4 be the final answer?arrow_forwardMass (g) Height (cm) Diameter (cm) Cylinder A 15.560 5.11 1.20 Cylinder B 35.536 5.90 1.30 In your calculation use the value 3.14 for π. Write your answer to the correct number of significant figures. Calculate the volume of Cylinder A and B using the dimensions of the cylinder.arrow_forwardI. Significant Figures and Conversion A. Scientific Notation 1. 58 cm → km 2. 67 W → MW 3. 196 mL L 4. 17 dm – cm 5. 299 W → TWarrow_forward
- digits when measurements are multiplied o... Multiply or divide the following measurements. Be sure each answer you enter contains the correct number of significant digits. 7.81 x 0.6 mL =g ml. mol 846.32 mol + 0.29 L %3D L. mol x 15. L L. = |mol 78.1arrow_forwardWhen you perform the following operations, how many significant figures should your answer have? Assume these are measured quantities. 312.3415 + 0.0100 = 07 8. 1 3 6.arrow_forward11. Calculate the area ofa circle with a radius of 10.0 m. Express your answer in square centimeters ( cm?). A = r² .arrow_forward
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