Chapter 1, Problem 1.55E

Find the difference between the value of x2 and the sum of x1 plus x3.; let x4 be equivalent to the sum of x1 and x3 and let x5 be the difference between x2 and x5. This calculation scheme is shown below. Make notes about any similarities or differences between the values in your notes.  x4 = x1 + x3 x5 = x2 – x4  Data Analyis  This section will include all data collected during the lab.    Thermochemical Data    Tinitial (°C)  Tfinal (°C)  ΔT (°C)  moles NaOH  qreaction (kJ)  ΔHrxn  Reaction 1  25.0    30.3    +5.3    0.025  -1.11    -44.4  Reaction 2  25.0    37.0    +12.0    0.025  -2.51    -100.4  Reaction 3  25.0    31.7    +6.7    0.025  -1.40    -56.1    Reaction 1: NaOH(s) → Na+(aq) + OH-(aq) + x1 kJ  1g /39.977g/mol = 0.025 moles  Moles NaOH = 0.025  qsolution = (4.184 J/g °C) (50.0g) (30.3°C -25.0°C)  = -1108.76 J/ 1000  qreaction (kJ) = -1.11 kJ   ΔH = -1.11 kJ/ 0.025 moles  ΔHrxn = -44.4 kJ/mol…

Conversion Factors in Calculations Report Sheet - Lab 2 B. Signlficant Figures in Calculations B.1 Perform the following multiplication and division calculations. Give a final answer with the correct number of significant figures: 4.5 x 0.28 0.1184 x 8.00 x 0.0345 (42.4)(15.6) 1.265 (35.56)(1.45) (4.8)(0.56) B.2 Perform the following addition and subtraction calculations. Give a final answer with the correct number of significant figures. Pre settin 2-Line entry of up Entry Line). 11 digits scrolf line. Press 2nd immediately to the The second line (Res digits, plus a decimal po indicator, and a 2-digit pos Results that exceed the digr Notation. Indicator Definition 2nd function. 2nd UVD Hunohali

Bob and Jill are measuring the height of Mr. Chenet (Mr Chenet is 1.8593 meters tall). Bob gets a measurement of 1.6329, while Jill gets a measurement of 1.8. This means that Bob is more accurate, while Jill is more precise.  True or False?

a. 23.25 + 625 = b. 58.175 – 45.06 = %3D c. 1000. × 2.68 =

6. Perform the following calculations and report each answer with the correct number of significant figures. (53.9 +11.21) x 10.3

Perform the following calculations to the correct number significant figures. (23.4813 x 2.52) + 374.99

Assignment/take Covalent Activity.do?locator=assignment-take $ 4 Submit Answer [Review Topics] [References] Use the References to access important values if needed for this question. a. When 68.938 and 17.6 are added, the answer should be based on 2 significant figure(s). Enter the answer with the correct number of digits. 68.938 +17.6 = 104.54 decimal place(s) b. When 99.137 is divided by 44.926, the answer should be based on 2✔ significant figure(s) Enter the answer with the correct number of digits. 99.137 44.926= 2.21 F4 % 5 Retry Entire Group 4 more group attempts remaining F5 Cengage Learning Cengage Technical Support 6 MacBook Air F6 & 7 A F7 * CO ㅊ입 ▷II F8 ( 9 4 F9 ) A O F10 VOTING NOVE us.shein.com SHEIN X VACA CONTEST art would you II Previous Email Instructor F11 + 11

Two students determine the percentage of lead in a sample as a laboratory exercise. The true percentage is 22.52 %. The students' results for three determinations are as follows: 1. 22.52, 22.28, 22.74 (Student A) 2. 22.64, 22.58, 22.62 (Student B) Calculate the average percentage for each set of data, and state which set is the more accurate based on the average? A. 22.51, Student A B. 22.55, Student A C. 22.51, Student B D.  22.55, Student B

To divide numbers in scientific notation: divide the digit terms and subtract the exponents. (A x 10)/(B x 10²) (A/B) x 10 Y-z (5.6 x 105)/(1.8 x 10²) = (5.6/1.8) x 105-2 (You may have to put numbers back in proper notation!) Perform these calculations (2.2 x 104) (1.3 x 10²) = (1.6 x 1033)/(1.3 x 10-6) = (4.6 x 1022) (1.2 x 10-8) = (5.6 x 107)/(1.0 x 10²) = (2.6 x 10²) (1.1 x 10-²) = = 3.1 x 10³ not used this semester. Before Adding and subtracting in scientific notation performing this function you must make the exponents the same first. 1.0 x 102 Example: 1.2 x 105 + You can't just add the digit terms because one is really a very large number so either take them both out of notation then add 120000 + 100 = 120100 or write one of the numbers out of proper notation in order to get the same exponent: now write in proper notation 1.201 x 105 1200 x 102 +1.0 x 10² = 1201 x 10²