* Asiacell Ilı.docs.google.com a4. For the code below, if num=12331, the output message "Thenumber is true" will be printed.#include using namespace std;int main()int n, num, digit, rev = 0;cout « "Enter a positive number: ";cin >> num;n - num;do{digit = num % 10;rev - (rev 10) + digit;num - num / 10;} while (num !- 0);cout <« " The reverse of the number is: " <« rev « endl;if (n - rev)cout <« " The number is True.";elsecout <« " The number is False.";return 0;O TrueO False5. For the following code if.

ZAV • Asiacell li. docs.google.com 4. For the code below, if num= 12331, the output message "The number is true" will be printed. include ciostream> using namespace std; int main() int n, num, digit, rev = 0; cout « "Enter a positive number: "; cin >> num: n- num; do digit = num x 10; rev - (rev 10) + digit; num- num / 10; } while (num 1= e); cout <« " The reverse of the number is: " « rev « endl; if (n rev) cout « " The number is True."; else cout « " The number is False."; return e; True O False

ZAV • Asiacell li. docs.google.com 4. For the code below, if num= 12331, the output message "The number is true" will be printed. include ciostream> using namespace std; int main() int n, num, digit, rev = 0; cout « "Enter a positive number: "; cin >> num: n- num; do digit = num x 10; rev - (rev 10) + digit; num- num / 10; } while (num 1= e); cout <« " The reverse of the number is: " « rev « endl; if (n rev) cout « " The number is True."; else cout « " The number is False."; return e; True O False

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

here is a and b part plz solve c part #include <iostream>#include <string.h>#include <stdlib.h>#include <sstream>#include <cmath>using namespace std; int main(){   /*Variable declarations*/int higestDegree,higestDegree1;int diffDegree,smallDegree;std::stringstream polynomial,addpolynomial;/*prompt for degree*/std::cout<<"Please enter higest degree of polynomial"<<std::endl;std::cin>>higestDegree; std::cout<<"Please Enter highest degree of 2nd polynomial"<<std::endl;std::cin>>higestDegree1;int *cofficient=new int[higestDegree+1];//cofficient array creation for 1st polynomailint *cofficient1=new int[higestDegree1+1];//cofficient array creation for 2st polynomail /*taking cofficient for 1st polynomial*/std::cout<<"Please enter cofficient of each term from higest degree to lowest for 1st polynomial"<<std::endl;for(int i=0;i<=higestDegree;i++){std::cin>>cofficient[i];}/*taking cofficient for 2st…
//I need help debugging the C code below the image is what I was following for directions while doing the code// #include <stdio.h> #include <stdlib.h> struct employees {     char name[20];     int ssn[9];     int yearBorn, salary; }; // function to read the employee data from the user void readEmployee(struct employees *emp) {     printf("Enter name: ");     gets(emp->name);     printf("Enter ssn: ");     for (int i = 0; i < 9; i++)         scanf("%d", &emp->ssn[i]);     printf("Enter birth year: ");     scanf("%d", &emp->yearBorn);     printf("Enter salary: ");     scanf("%d", &emp->salary); } // function to create a pointer of employee type struct employees *createEmployee() {     // creating the pointer     struct employees *emp = malloc(sizeof(struct employees));     // function to read the data     readEmployee(emp);     // returning the data     return emp; } // function to print the employee data to console void display(struct…
//I need help debugging the C code below the image is what I was following for directions while doing the code// #include <stdio.h> #include <stdlib.h> struct employees {     char name[20];     int ssn[9];     int yearBorn, salary; }; // function to read the employee data from the user void readEmployee(struct employees *emp) {     printf("Enter name: ");     gets(emp->name);     printf("Enter ssn: ");     for (int i = 0; i < 9; i++)         scanf("%d", &emp->ssn[i]);     printf("Enter birth year: ");     scanf("%d", &emp->yearBorn);     printf("Enter salary: ");     scanf("%d", &emp->salary); } // function to create a pointer of employee type struct employees *createEmployee() {     // creating the pointer     struct employees *emp = malloc(sizeof(struct employees));     // function to read the data     readEmployee(emp);     // returning the data     return emp; } // function to print the employee data to console void display(struct…
1. What is the output of the following code segment: char* s [] = { "NBY", "SDT"}; const char** z = s; const cout << z [1] [1]; cout << cout << a. DSDT b. DTY c. DTBY d. DTS e. *(z [1]+ 2); (*z + 1); None of the above
//I need help debugging the C code below the image is what I was following for directions while doing the code// #include <stdio.h> #include <stdlib.h> struct employees { char name[20]; int ssn[9]; int yearBorn, salary; }; // function to read the employee data from the user void readEmployee(struct employees *emp) { printf("Enter name: "); gets(emp->name); printf("Enter ssn: "); for (int i = 0; i < 9; i++) scanf("%d", &emp->ssn[i]); printf("Enter birth year: "); scanf("%d", &emp->yearBorn); printf("Enter salary: "); scanf("%d", &emp->salary); } // function to create a pointer of employee type struct employees *createEmployee() { // creating the pointer struct employees *emp = malloc(sizeof(struct employees)); // function to read the data readEmployee(emp); // returning the data return emp; } // function to print the employee data to console void display(struct…
Explain the code and how it works: #include <iostream>#include <cmath> using namespace std;double to_kilograms(double n){ return n * 0.453592;}double to_pounds(double n){ return n * 2.20462;}double to_kilograms_ref(double& n){ return n * 0.453592;}double to_pounds_ref(double& n){ return n * 2.20462;}double to_kilograms_ptr(double* n){ return *n * 0.453592;}double to_pounds_ptr(double* n){ return *n * 2.20462;} void display_menu(){ cout << "1.Kilograms to Pounds (pass by value)\n2. Pounds to Kilograms (pass by value)\n3. Kilograms to Pounds (pass by reference)\n4. Pounds to Kilograms (pass by reference)\n5. Kilograms to Pounds (using pointers)\n6. Pounds to Kilograms (using pointers)\nEnter choice\n\n";} void convert(){ int ch; double w; cout << "Enter a menu option: "; cin >> ch; cout << "Enter weight: "; cin >> w; if (ch == 1) cout << "weight in kg is " << to_kilograms(w);…
Please fix this code for me, I'm stuck . #include<iostream>#include <iomanip>using namespace std;// the main bodyint main(){std::string item[10],name;int n;float price[10],ST_VAT[10],tax[10],total=0.0,Net;cout<<"Enter the number of items that should be atleast 5 : ";cin>>n;cout<<"Enter the customer's name ";cin>>name;for(int i=1;i<=n;i++){ std::cout<<"\nEnter the item "<<i<<" name , cost, sales tax and VAT :";cin>>name>>price[i]>>ST_VAT[i];tax[i]=price[i]+ST_VAT[i];total=total+tax[i];}Net=total-0.05*total;cout<<swet(5)<<"Food Stuff Grocery Shop"<<endl;cout<<"Customer Name"<<name<<endl;cout<<"ITEM"swet(8)<<"PRICE"<<swet(15)"Sales Tax+ VAT"<<swet(10)<<Sub-Total endl;cout<<SWET(8)<<"------------"<<swet(15)<<"--------------"<<swet(10)<<"----------"endl;for(int…
plz make this code from this to enter number from 1-8 to let the user play and put all the notes, basically make this code 8 queen puzzle game to make the user play. #include <stdio.h>#include <stdlib.h> int count = 0;void solve(int n, int col, int *hist){ if (col == n) { printf("\nNo. %d\n-----\n", ++count); for (int i = 0; i < n; i++, putchar('\n')) for (int j = 0; j < n; j++) putchar(j == hist[i] ? 'Q' : ((i + j) & 1) ? ' ' : '.'); return; } # define attack(i, j) (hist[j] == i || abs(hist[j] - i) == col - j) for (int i = 0, j = 0; i < n; i++) { for (j = 0; j < col && !attack(i, j); j++); if (j < col) continue; hist[col] = i; solve(n, col + 1, hist); }} int main(int n, char **argv){ if (n <= 1 || (n = atoi(argv[1])) <= 0) n = 8; int hist[n]; solve(n, 0, hist);}
1. Examine the following code segment. What will be printed?If there are any errors indicate the nature of the error. int a[8] ={16, 12, 10, 7, 15, 18, 17, 29}; int *ptr ; ptr = & a[ 5 ] ; for(int i = 0; i<= 4; i = i + 2) cout<<a[i]<<*( ptr + i )<<endl; cout<<” ”<<a[1]<<” ”<<*ptr<<” ”<<*ptr + 2<<” ”<<*(ptr + 3);
C++ 2D ARRAY, Continue this codes and change the array to seat[6][6]. Include a loop that asks the user if he wants to try again or no. If the user enters the reserved seat again then display "this seat is taken already". Upon trying again, the reserved seat displayed as (X) must be displayed. My Code: #include <iostream> using namespace std; int main() { cout << "Bus Seats:\n"; cout << "* A B C D\n" << "1 * * * *\n" << "2 * * * *\n" << "3 * * * *\n" << "4 * * * *\n"; char seat[5][5]; int row, column; char col; cout << "Enter the row of your selected seat: "; cin >> row; cout << "Enter the column of your selected seat: "; cin >> col; for(int i=0; i<5; i++){ for(int j=0; j<5; j++){ if(i==0){ switch (j) { case 0: seat[i][j]='*'; break; case 1: seat[i][j]='A'; break; case 2: seat[i][j]='B'; break; case 3: seat[i][j]='C'; break; case 4: seat[i][j]='D'; break; } } else if (j==0) { switch(i) { case 1: seat[i][j]='1';…