Your roommate argues that the ring form of glucose can react with methanol to form an intermolecularhemiacetal without being converted to the open chain form. Do you agree with your roommate? Pleaseexplain your reasoning.

In solution, glucose is mostly found in the cyclic hemiacetal state, which lacks an aldehyde group. How are mild oxidising agents able to oxidise glucose?

Please answer in tipping format

Chiral Carbons print/draw the expanded structure of 4-bromo-4-ethylhept-1-ene. Determine if your molecule contains any chiral carbons. If there are chiral carbons in your molecule, circle or highlight all of them. If your molecule does not contain any chiral carbons explain why none of the carbons are chiral.