Your object has mass 59.8 kg, and you ve separated the boxes of protons and electrons by a distance of 27 m. If you were to release the clump of protons from their box, how much acceleration would the clump of protons undergo due to its attraction to the clump of electrons in the other box?

Consider the electrostatic force between two particles of equal mass m = 25.6 × 10-26 kg and carrying different charges q1 = 14e and q2 = 28e, where e denotes the magnitude of the charge on an electron. At what distance, in meters, is the electrostatic force between these two particles equal to the weight of one of them?

THIS IS THE PREVIOUS QUESTION IT IS REFERRING TOO!! Your object has a mass of 35.6 kg. You separate an equal amount of protons and electrons into two boxes. You place the boxes at a distance of 80 m apart from one another. How much force attracts the two boxes to one another?                           Similar situation to the previous question, but now the object s mass is 60.0 kg and you initially put the boxes of protons and electrons 24 m apart. Now you want to take the two boxes and move them farther apart, to a new distance of 45 m apart. How much work (that is, energy) would you have to expend to pull the boxes that much farther apart, fighting against the electrostatic attraction between them?     1.44E+27 J     2.88E+27 J     5.76E+27 J     7.20E+26 J

and F represents gravitational and electrostatic force respectively between electrons situated at a distance 10 cm. The ratio of F/F is of the order of e (a) 1042 (c) 1024 (b) 10-²1 F g (d) 10-43 KAL

Pleae help solve for magnitude.

Air breaks down (loses its insulating quality) and sparking results if the field strength is increased to about 3.0 x 106 N/C. a) What acceleration does an electron experience in such a field (me=9.11x10’31kg)? (b) if the electron starts from rest, in what distance does it acquire a speed equal to 10% of the speed of light (3x107 m/s)?

A simple and common technique for accelerating electrons is shown in the figure below, where a uniform electric field is created between two plates. Electrons are released, usually from a hot filament, near the negative plate, and there is a small hole in the positive plate that allows the electrons to continue moving. (a) Calculate the acceleration of the electron if the field strength is 3.45 x 104 N/C. m/s² (b) Why will the electron not be pulled back to the positive plate once it moves through the hole? O The force of gravity is too strong. O There is no field outside the plates. O The other side of the positive plate also has a negative charge.

Electric forces between two charged objects tend to be much stronger in magnitude than the attractive gravitational force between them. Two particles of masses 7.61 kg and 9.37 kg and charges 9.17 μC and -6.51 µC respectively are separated by a distance 11.1 cm. Find the magnitude of the ratio of the gravitational to electric forces between them. ratio =

provides some pertinent background for this problem. Suppose a single electron orbits about a nucleus containing two protons (+2e), as would be the case for a helium atom from which one of the naturally occurring electrons is removed. The radius of the orbit is 3.09 × 10-11 m. Determine the magnitude of the electron's centripetal acceleration.

An electron is circularly orbiting a proton. The magnitude of acceleration of the electron is 1.44×10–8 m/s2 . What is the electron’s orbital radius?