your ID No., kN/m) uniformly distributed load will be applied in the entire beam span and another 15 kN/m (plus half of the last two digits of your ID No., kN/m) uniformly distributed load will be applied in column. The beam section is illustrated in Figure 2b. Hint: after solving vertical reaction in the roller support, cut the beam 6 m from the roller support to get the moment for flexural stress
your ID No., kN/m) uniformly distributed load will be applied in the entire beam span and another 15 kN/m (plus half of the last two digits of your ID No., kN/m) uniformly distributed load will be applied in column. The beam section is illustrated in Figure 2b. Hint: after solving vertical reaction in the roller support, cut the beam 6 m from the roller support to get the moment for flexural stress
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
Don't be confused, the 10 kn will be 18 kn and 15kn/m will be 31 kn/m. Disregard the id things.
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![Determine the flexural compressive and tensile (kPa) stresses 6 m from the roller support of the
beam in the frame structure shown in Figure 2a, if 10 kN/m (plus quarter of the last two digits of
your ID No., kN/m) uniformly distributed load will be applied in the entire beam span and another 15
kN/m (plus half of the last two digits of your ID No., kN/m) uniformly distributed load will be
applied in column. The beam section is illustrated in Figure 2b. Hint: after solving vertical reaction
in the roller support, cut the beam 6 m from the roller support to get the moment for flexural stress
100
200
100 1 100 100
40 KN
4 m
50 KN
4 m
600
7 m
4 m
(a)
(b)
Figure 2. Frame structure with: (a) applied loads, and (b) bcam scction in mm units
001 T COLT OL
COLT 00L](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff055d95c-318d-4edc-8b2d-c5f7c609473f%2F80569447-c9bd-41ea-885d-06a20d97d91a%2Ft48njg_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Determine the flexural compressive and tensile (kPa) stresses 6 m from the roller support of the
beam in the frame structure shown in Figure 2a, if 10 kN/m (plus quarter of the last two digits of
your ID No., kN/m) uniformly distributed load will be applied in the entire beam span and another 15
kN/m (plus half of the last two digits of your ID No., kN/m) uniformly distributed load will be
applied in column. The beam section is illustrated in Figure 2b. Hint: after solving vertical reaction
in the roller support, cut the beam 6 m from the roller support to get the moment for flexural stress
100
200
100 1 100 100
40 KN
4 m
50 KN
4 m
600
7 m
4 m
(a)
(b)
Figure 2. Frame structure with: (a) applied loads, and (b) bcam scction in mm units
001 T COLT OL
COLT 00L
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