Hi, please explain why my answer is wrong (as the Wiley system stated) and also, I will appreciate if you include the correct answer. My solution looks like this, thank you Your answer is partially correct.A student (m -63 kg) falls freely from rest and strikes the ground. During the collision with the ground, he comes to rest in a time of0.04s. The average force exerted on him by the ground is +18000 N, where the upward direction is taken to be the positive direction.From what height did the student fall? Assume that the only force acting on him during the collision is that due to the ground.H- 6.7eTextbook and MediaGO TutorialHi, please explain why my answer is wrong (as the Wiley system stated) and also, I will appreciate if youinclude the correct answer. My solution looks like this, thank you:Chapter 7: 4, 11, 12, 19. Students may still have questions from chapter 6, so please kindly work withthem if time permits.mSOLUTION We begin with the energy conservation principlem+mgh =mv+mgh (Equation 6.9b) applied to the student's fall to the ground. Falling from rest impliesvo= 0 m/s, and the student's final velocity is the impact velocity: v=Vimpact . Thus, we have(1)0+ mgh = 1 mv²2 impactH =impact2g+mgh or(2)Vo=VimpactSubstituting Equation (2) into Equation (1) yieldsmHIFor the student's collision with the ground, the impulse-momentum theorem givesFground Atmy-mv (Equation 7.4). The collision brings the student to rest, so we know thatv=0 m/s, and Equation 7.4 becomes Fground At=-mv. Solving for the impact speed vo, we obtainFground AfF8(h-h)=2pct2 impactground Arm2g²impact2gII =or(Fground At) [(+18 000 N)(0.040 s)]²2gm²2(9.80 m/s²) (63 kg)²= 6.7 m

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Your answer is partially correct. A student (m -63 kg) falls freely from rest and strikes the ground. During the collision with the ground, he comes to rest in a time of 0.04s. The average force exerted on him by the ground is +18000 N, where the upward direction is taken to be the positive direction. From what height did the student fall? Assume that the only force acting on him during the collision is that due to the ground. 6.7 m

Your answer is partially correct. A student (m -63 kg) falls freely from rest and strikes the ground. During the collision with the ground, he comes to rest in a time of 0.04s. The average force exerted on him by the ground is +18000 N, where the upward direction is taken to be the positive direction. From what height did the student fall? Assume that the only force acting on him during the collision is that due to the ground. 6.7 m

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter11: Collisions

Section: Chapter Questions

Problem 8PQ

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