Your -2 regression of 43 observations and 5 regressors shows a R = 0.29. What is the value of R²? Enter your answer with two decimal places.
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Q: A regression analysis was performed to determine if there is a relationship between hours of TV…
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Q: A regression was run to determine if there is a relationship between hours of TV watched per day (x)…
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Q: A regression analysis was performed to determine if there is a relationship between hours of TV…
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- Does how long young children remain at the lunch table help predict how much they eat? Twenty toddlers were observed over several months at a nursery school. "Time" is the average number of minutes a child spent at the table when lunch was served. "Calories" is the average number of calories the child consumed during lunch, calculated from careful observation of what the child ate each day. A regression was run and the results were: = 114 + 2.4*x R² = 0.68 r = 0.822 Predict the number of calories a toddler consumes who remains at the table for 14.5 minutes (round your answer to two decimal places)A regression was run to determine if there is a relationship between hours of TV watched per day (x) and number of situps a person can do (y). The results of the regression were: ŷ=ax+b a=-0.643 b=32.437 r²=0.570025 r=-0.755 Use this to predict the number of situps a person who watches 2 hours of TV can do (to one decimal place)ABC University uses data from a random sample of students in a regression analysis to see i he number of hours a student spends playing video games weekly (x) is a predictor of the student's GPA (y) at the end of the term. An intern for ABC goes ahead and performs the regression using Excel. Examine the following Excel regression printout. Describe what the value -0.0292...in the cell next to "X Variable 1" label means. SUMMARY OUTPUT Regression Statistics Multiple R R Square Adjusted R Square 0.709640286 0.503589336 0.45394827 Standard Error 0.552383099 Observations 12 ANOVA df SS MS Regression 3.095395785 3.09539579 28 72.28745 Residual 10 3.051270881 0.3051270937 Total 11 6.146666667 Coefficients Standard Error t Stat P-value Interce pt X Variable 1 3.46198431 0.296274535 11.6850552 11 1.94E-10 -0.029275496 0.009191503 -3.1850607 37 6.88E-06 Regression should not be used on the data set. The correlation coefficient is -0.0292 when rounded to 3 places. The regression line has a…
- A regression was run to determine if there is a relationship between hours of TV watched per day (xx) and number of situps a person can do (yy).The results of the regression were:y=ax+b a=-0.853 b=34.041 r2=0.389376 r=-0.624 Use this to predict the number of situps a person who watches 7 hour(s) of TV can do, and please round your answer to a whole number.A regression was run to determine if there is a relationship between hours of study per week (xx) and the test scores (yy). The results of the regression were: y=ax+b a=5.709 b=34.57 r2=0.641601 r=0.801 Use this to predict the score of a student who studies 9.5 hours per week, and please round your answer to a whole number.The data show the bug chirps per minute at different temperatures. Find the regression equation, letting the first variable be the independent (x) variable. Find the best predicted temperature for a time when a bug is chirping at the rate of 3000 chirps per minute. Use a significance level of 0.05. What is wrong with this predicted value? Chirps in 1 min 784 838 822 949 1188 813 Temperature (°F) 65.7 67.8 66.2 79.9 92.3 73.5 What is the regression equation? What is the best-predicted temperature for a time when a bug is chirping at the rate of 3000 chirps per minute? The best predicted temperature when a bug is chirping at 3000chirps per minute are? What is wrong with this predicted value? Choose the correct answer below. A. It is unrealistically high. The value 3000 is far outside of the range of observed values. B. The first variable should have been the dependent variable. C. It is only an…
- A regression was run to determine if there is a relationship between hours of study per week (z) and the test scores (y)- The results of the regression were: y=ax+b a=5.701 b=31.89 r2=0.660969 r=0.813 Use this to predict the final exam score of a student who studies 3.5 hours per week, and please round your answer to a whole number. Question Help: Message instructor Submit Question rse here to search RA regression was run to determine if there is a relationship between hours of study per week (xx) and the final exam scores (yy).The results of the regression were: y=ax+b a=6.22 b=21.6 r2=0.477481 r=0.691 Use this to predict the final exam score of a student who studies 8 hours per week, and please round your answer to a whole number.The data show the bug chirps per minute at different temperatures. Find the regression equation, letting the first variable be the independent (x) variable. Find the best predicted temperature for a time when a bug is chirping at the rate of 3000 chirps per minute. Use a significance level of 0.05. What is wrong with this predicted value? Chirps in 1 min 760 1119 1125 850 965 785 D Temperature (°F) 70.5 90.8 90.8 74.7 77.1 69.9 What is the regression equation? (Round the x-coefficient to four decimal places as needed. Round the constant to two decimal places as needed.)
- A regression was run to determine if there is a relationship between hours of study per week (�) and the test scores (�).The results of the regression were:y=ax+b a=6.254 b=33.41 r2=0.976144 r=0.988 Use this to predict the final exam score of a student who studies 3 hours per week, and please round your answer to a whole number.A regression was run to determine if there is a relationship between hours of TV watched per day (x) and number of situps a person can do (y). The results of the regression were: y=ax+b a=-0.698 b=37.226 r2=0.799236 r=-0.894 Use this to predict the number of situps a person who watches 14 hours of TV can do (to one decimal place)A regression was run to determine if there is a relationship between hours of study per week (x) and the final exam scores (y). The results of the regression were: y=ax+b a=6.239 b=38.43 r²=0.758641 r=0.871 Use this to predict the final exam score of a student who studies 6 hours per week, and please round your answer to a whole number.