MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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Question
You wish to test the following claim (HaHa) at a significance level of α=0.05α=0.05.
Ho:μ=76.7Ho:μ=76.7
Ha:μ≠76.7Ha:μ≠76.7
You believe the population is
Data |
---|
64.2 |
64.2 |
76.7 |
79.4 |
69.4 |
107.5 |
94.6 |
80.9 |
107.5 |
98.8 |
71.6 |
66.7 |
60.8 |
57.4 |
95.1 |
82.3 |
84.5 |
82.0 |
102.3 |
82.7 |
88.8 |
79.8 |
75.8 |
73.6 |
93.7 |
57.4 |
83.0 |
74.5 |
60.8 |
100.8 |
79.0 |
75.0 |
82.0 |
62.0 |
80.1 |
81.2 |
62.0 |
86.3 |
79.0 |
91.6 |
104.1 |
70.0 |
75.8 |
81.6 |
68.1 |
- What is the test statistic for this sample?
test statistic = Round to 3 decimal places - What is the p-value for this sample?
p-value = Use Technology Round to 4 decimal places. - The p-value is...
- less than (or equal to) αα
- greater than αα
- This test statistic leads to a decision to...
- reject the null
- accept the null
- fail to reject the null
- As such, the final conclusion is that...
- There is sufficient evidence to warrant rejection of the claim that the population
mean is not equal to 76.7. - There is not sufficient evidence to warrant rejection of the claim that the population mean is not equal to 76.7.
- The sample data support the claim that the population mean is not equal to 76.7.
- There is not sufficient sample evidence to support the claim that the population mean is not equal to 76.7.
- There is sufficient evidence to warrant rejection of the claim that the population
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- The lengths of time (in years) it took a random sample of 32 former smokers to quit smoking permanently are listed. Assume the population standard deviation is 5.3 years. At α = 0.08, is there enough evidence to reject the claim that the mean time it takes smokers to quit smoking permanently is 15 years? Complete parts (a) through (e). 8.4 11.8 19.1 16.5 22.7 11.3 16.7 15.8 18.5 14.1 8.2 9.5 16.7 20.1 22.9 11.3 16.8 20.3 14.5 17.1 14.9 (a) Identify the claim and state the null hypothesis and alternative hypothesis. O A. Ho: μ≤ 15 (claim) H₂:μ>15 14.7 16.2 20.2 14.5 15.1 22.1 11.1 21.5 19.6 17.1 16.6 O D. Ho: H15 (claim) H₂:μ#15 O B. Ho: μ ≥ 15 (claim) H₂:µ 15 (claim) H₂:μ≤15 a O C. Ho: μ15 (claim) H₂:μ=15 OF. Ho: H> 15 H₂: μs 15 (claim)arrow_forwardYou wish to test the following claim (Ha) at a significance level of a = 0.05. Ho : p = 87.7 H : μ > 87.7 You believe the population is normally distributed, but you do not know the standard deviation. You obtain the following sample of data: data 91.6 98.8 128.9 112.1 92.2 What is the test statistic for this sample? (Report answer accurate to 3 decimal places.) test statistic = What is the P-value for this sample? (Report answer accurate to 3 decimal places.) P-value =arrow_forwardWhich of the following options correctly describes how to obtain the estimated standard error in a single sample t-test? a. Divide the population standard deviation by the sample size b. Divide the population standard deviation by the square root of the sample size c. Divide the sample standard deviation by the sample size d. Divide the sample standard deviation by the square root of the sample sizearrow_forward
- You wish to test the following claim (Ha) at a significance level of a = 0.02. H.:µ = 78.8 Ha:u # 78.8 You believe the population is normally distributed, but you do not know the standard deviation. Yo- the following sample of data: data 89.8 93.6 83.4 91.5 What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is... O less than (or equal to) a O greater than a This test statistic leads to a decision to... O reject the null O accept the null O fail to reject the null As such, the final conclusion is that... O There is sufficient evidence to warrant rejection of the claim that the population mean is not e to 78.8. O There is not sufficient evidence to warrant rejection of the claim that the population mean is n equal to 78.8. O The sample data support the claim that the population mean is not equal to 78.8. O There is not…arrow_forwardConsider the following data: x 4 5 6 7 8 P(X = x) 0.2 0.2 0.1 0.2 0.3 Step 3 of 5: Find the standard deviation. Round your answer to one decimal place. Copy Dataarrow_forwardThe results of a certain medical test are normally distributed with a mean of 123 and a standard deviation of 20. Convert the given results into z-scores, and then use the table below to find the percentage of people with readings between 151 and 171. z-score Percentile z-score Percentile 1.0 84.13 2.1 98.21 1.1 86.43 2.2 98.61 1.2 88.49 2.3 98.93 1.3 90.32 2.4 99.18 1.4 91.92 2.5 99.38 -C 1.5 93.32 2.6 99.53 The percentage of people with readings between 151 and 171 is %. (Round the final answer to the nearest hundredth as needed. Round the z-score to the nearest tenth as needed.) 1.6 94.52 2.7 99.65 1.7 95.54 2.8 99.74 1.8 96.41 2.9 99.81 1.9 97.13 3.0 99.87 2.0 97.72 3.5 99.98arrow_forward
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