You wish to test the following claim (Ha) at a significance level of a = 0.05. H.:µ = 61.1 Ha:µ + 61.1 %3| You believe the population is normally distributed and you know the standard deviation is o = 5.8. You obtain a sample mean of M = 62.1 for a sample of size %3D n = 62. What is the critical value for this test? (Report answer accurate to three decimal places.) critical value = ± What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic %3D

You wish to test the following claim (Ha) at a significance level of a = 0.005. H,:µ = 90.6 Ha:µ < 90.6 You believe the population is normally distributed, but you do not know the standard deviation. You obtain the following sample of data: data 95.7 78.9 81.3 What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is... Oless than (or equal to) a greater than a

I need help with question b

The 2011 gross sales of all firms in a large city has a mean of $2.5 million and a standard deviation of $0.6 million. Using Chebyshev's theorem, find at least what percentage of firms in this city had 2011 gross sales of $1.2 to $3.8 million:   You are going to apply the Z-score for Normal Distribution and the Area of the Curve for this problem:   1. Sample Mean = 2.5 2. Standard Deviation = .6 3. X = 1.2 (X = data point)  4. X = 3.8   1st Step is to find the Z-score associated to X = 1.2    z=   X - μ         σ    z=   1.2 - 2.5        .6   z = -1.3    .6   Z = -2.16     Now you need to find the Z-score associated to X = 3.8     z=   X - μ         σ    z=   3.8 - 2.5         .6     z=   1.3        .6   Z = +2.16     You need to find the area of the curve that covers Z = -2.16 to Z = +2.16   Go to your Normal Distribution Table in this room   Break up 2.16 into 2.1 on the vertical and .06 on the vertical........What is at the intersection? The area of the Curve from Z = 0 to Z = +2.16…