You wish to make a 0.213 M hydrobromic acid solution from a stock solution of 3.00 M hydrobromic acid. How much concentrated acid must you add to obtain a total volume of 150 mL of the dilute solution? ___mL

If 0.500 mL of an 0.219 M NaCl solution is added to 100.0 mL of pure water.  what is the concentration of the new solution? Your answer should have 3 sig figs

You have a 2.00 M solution of sucrose and need to use it to make 1.0 L of a 0.500 M solution of sucrose. You will take _____ mL of that 2.00 M solution and add enough water to make 1.00 L of the new solution.

The stock solution in the stock beaker contains 10.00 mL of 0.1000 M iron(III) nitrate solution, 10.00 mL of 0.1000 M potassium thiocyanate solution, and 10.00 mL of 0.5000 M nitric acid solution.   What is the total volume of the stock solution?  How many moles of iron (III) nitrate are present in the stock solution?      How many moles of potassium thiocyanate are present in the stock solution?        Based on the moles of iron (III) nitrate and moles of potassium thiocyanate, how many moles of iron (III) thiocyanate do you expect to be formed    Once you determine the moles of iron (III) thiocyanate formed, determine the concentration of iron (III) thiocyanate in the final solution.