
Elements Of Electromagnetics
7th Edition
ISBN: 9780190698614
Author: Sadiku, Matthew N. O.
Publisher: Oxford University Press
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Transcribed Image Text:You will start by getting used to the idea of the linear mass density by relating it to concepts you are already familiar with: the mass and the (volume mass) density.* First, you have a column of pure
water that has a density PH₂0 = 1 g/cc. The water column is in a cylinder. The column has cross-sectional area 31 cm² and height 75 cm before salt is added.
The linear mass density has two different definitions. One is going up in dimensionality, that is from the volume mass density p to the linear mass density
λ = PA
where A is the cross-sectional area of the object. The other is going down in dimensionality, that is from the mass down to the linear mass density
λ = M
H
where H is the height of the column in our case. You will use both of these below:
(a) What is the linear mass density of the water column?
ÅH20 =
(b) What is the mass of the water?
M =
Let's now try this after adding salt to the water. When we do, the column's height rises to a level 78 cm, and we measure its salinity to 54.5 9Naci/k9H20 (grams of salt per kilogram of water). Assume
that the solution is well-stirred at this point so that the salt is uniformly distributed.
We can now find the various quantities for the salt water, in reverse order.
(c) First, use dimensional analysis to find the mass of the salt water column.
M' =
(d) Next, find the linear mass density of the salt water column.
A' =
(e) Finally, find the volume mass density.
p' =
You should, at this point conjecture how to find the linear mass density of the salt water from the linear mass density of the pure water using only the salinity. Does your idea make sense physically? If
you implement it, does it match the value found in part (d)?
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