You want to obtain a sample to estimate the proportion of a population that possess a particular genetic marker. Based on previous evidence, you believe approximately p*= 23% of the population have the genetic marker. You would like to be 98% confident that your estimate is within 4% of the true population proportion. How large of a sample size is required? n = Do not round mid-calculation. However, you may use a critical value accurate to three decimal places.

Q: Let z be a standard normal random variable with mean ? = 0 and standard deviation ? = 1. Use Table 3…

A: Z has follows standard normal distribution with mean zero and standard deviation one.

Q: Please answer the photo attached in excel, please provide the formula too. Thank you

A: ABC7896658973032575655574544985656752322452224745556589999562395585821959997103662131211432

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A: The given data is as follows:

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A: alpha = 0.05difference = d = april weights - September weightsthere are total 9 samples so n=9…

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A: M=4N=11n=6

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A: From the provided information,

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A: n=980% confidence interval

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A: yx1x21001812312153141710101963231392517831186

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Q: Let z be a standard normal random variable with mean ? = 0 and standard deviation ? = 1. Use Table 3…

A: The probability shows how likely an event occurs.

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A: BackgroundnsBlue504.420.53Red313.590.82

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A: Regression analysis is used when we want to predict value of dependent variable using given sample…

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A: standard deviation()=11sample size(n)=60Mean()=67confidence level=95%

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A: n1=14,n2=13,s12=8.318,s22=3.568

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A: It is given that Mean, μ = 64.1Std. deviation, σ = 2.6

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A: n=5P=0.703By using binomial distributionP(x=k) =

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