You perform the distillation of the cyclohexane/toluene mixture as shown in the JOVE Video. The starting solution contains 2mL of cyclohexane and 2 ml of toluene. At temperature of 95°C, a 1.5mL sample is collected and based on the boiling point
You perform the distillation of the cyclohexane/toluene mixture as shown in the JOVE Video. The starting solution contains 2mL of cyclohexane and 2 ml of toluene. At temperature of 95°C, a 1.5mL sample is collected and based on the boiling point
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Is my math correct and whats #3
Transcribed Image Text:Experiment:
You perform the distillation of the cyclohexane/toluene mixture
as shown in the JOVE Video. The starting solution contains 2mL
of cyclohexane and 2 ml of toluene. At temperature of 95°C, a
1.5mL sample is collected and based on the boiling point
diagram the composition of the vapors is 72/28 (consider that
the densities are identical for cyclohexane and toluene).
1. Calculate the volume of cyclohexane and volume of toluene
collected at 95°C.
Volume of vapor: total volume - volume of sample
(2+2)-1.5=2.5ml
Volume of cyclohexane: % hexane/total % * volume of vapor
(72/72+2.5)*2.5ml=1.8
Volume of toluene: % hexane/total % * volume of vapor
(28/72+28)*2.5-0.7
2. Calculate the ratio of cyclohexane/toluene remaining in the
boiling solution at 95°C.
Volume of cyclohexane in sample: (volume of total cyclohexane)-(volume of cyclohexane in vapor)
2-1.8=0.2
Volume of toluene in sample: (volume of total toluene)-(volume of toluene in vapor)
2-0.7=1.3
Ratio of cyclohexane and toluene is sample: 0.2ml/1.3ml=2/13
3. Discuss the reason for the different composition between the
vapor and the boiling solution at 95°C.
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