You may need to use the appropriate appendix table or technology to answer this question. A simple random sample of 90 items resulted in a sample mean of 60. The population standard deviation is  σ = 15. (a) Compute the 95% confidence interval for the population mean. (Round your answers to two decimal places.)  to  (b) Assume that the same sample mean was obtained from a sample of 180 items. Provide a 95% confidence interval for the population mean. (Round your answers to two decimal places.)  to  (c) What is the effect of a larger sample size on the interval estimate? A larger sample size provides a smaller margin of error.A larger sample size provides a larger margin of error.    A larger sample size does not change the margin of error.

Q: You measure 39 dogs' weights, and find they have a mean weight of 49 ounces. Assume the population…

A: Given,sample size(n)=39sample mean(x¯)=49standard deviation(σ)=6.8α=1-0.99=0.01α2=0.005Z0.005=2.58…

Q: You may need to use the appropriate appendix table or technology to answer this question. A simple…

A:

Q: A simple random sample with n= 53 provided a sample mean of 27.5 and a sample standard deviation of…

A: Sample size n =53Sample mean=27.5Sample standard deviation =4.4NOTE:- According to bartleby…

Q: #5: Calculate the chi-square test statistic, p-value, and effect size. Report the following measures…

A: Given Information: Month Frequency Observed Jan 0.0025 0 Feb 0.0075 1 March 0.02 5 April…

Q: Construct a confidence interval of the population proportion at the given level of confidence. x=…

A: Given :  x = 860 n = 1100 Confidence level = 96%

Q: Solve the following. Show your complete solution. Fifty randomly selected jeepneys were stopped, and…

A:

Q: Question 4 You have taken 10 observations from normally distributed data that is known to have a…

A: Given data: Population standard deviation = 1 Sample size = 10 Sample mean = 32 To calculate  the…

Q: The foot lengths of a random sample of 53 men had a mean of 27 cm and a standard deviation of 2 cm,…

A: Solution-:   Given: n1=53 (men), n2=100 (women), x1¯=27, x2¯=23.5, s1=2, s2=2, α=0.05 We want to…

Q: Part A: Make a 90% confidence interval for given that you have a sample of size 49 which produced a…

A: Given,margin of error(E)=0.2standard error(σ)=3.2α=1-0.90=0.10α2=0.05Z0.05=1.645      (from Z-table)

Q: QUESTION 9 Calculate the margin of error for an 80% confidence interval for the mean, when the…

A:

Q: 5. A random sample of 43 foreign language movies made since the year 2000 had a mean length of 112.5…

A: Here, the parent distribution from which the sample is taken is unknown and also, the population…

Q: 04 people who work in computer-related jobs, and found that 40 of them have 6 months. fidence…

A: We have given that favourable cases X = 40, sample size n = 204 Sample proportion p^ = X/n.

Q: In a survey of a random sample of 49 college students, the sample mean time per week spent watching…

A: We have given that,  Sample mean (x̄) = 21, sample size (n)= 49, and standard deviation (s) = 8.2…

Q: A researcher reported that the 99% z-confidence interval for the mean rainfall in UAE is (42.424 mm,…

A:

Q: question 2 A simple random sample of 70 items from a population with  7 resulted in a sample mean…

A: The given data is as follows:Sample size, Population standard deviation, Sample mean,

Q: We would like to construct a 99% confidence interval for the mean, based on a sample of 50…

A:

Q: Question 9 A botanist wishes to estimate the typical number of seeds for a certain fruit. She…

A:

Q: Mindy finds a 96% confidence interval for the mean height of American women. Kenny finds a 96%…

A: Confidence Interval: Confidence interval is the interval estimate of the population parameter. It is…

Q: The foot lengths of a random sample of 53 men had a mean of 27 cm and a standard deviation of 2 cm,…

A: Given, n1=53               n2=100 x1=27                x2=23.5 s1=2                  s2=2…

Q: An economist would like to estimate the average household income in Martin county. The mean…

A: We have given that,  Sample mean (x̄) = $ 52590, population standard deviation (σ ) = $ 864 and…

Q: Among various ethnic groups, the standard deviation of heights is known to be approximately three…

A:

Q: A range estimate at a 95% confidence level is intended to be given for the difference between the…

A: Given:  Sample size:   n1 = 40       &   n2 = 50            Sample mean:  M1 = 10    &   M2…

Q: Find a 90% confidence interval for the population mean age of the Smurfs if a sample of 52 smurfs…

A: It is given that, There is a random sample of size 52 and has a mean of 49.7 and the standard…

Q: The mean diastolic blood pressure for a random sample of 90 people was 82 millimeters of mercury. If…

A: Given that  Random sample size (n) = 90 Mean diastolic blood pressure (x¯)= 82 mmHg  Population…

Q: 2 Again use the data from Table [ Fifty randomly-selected Durham burials (1960-1969) ] . (a)…

A: 2. (a) The sample mean is, x¯=∑xn=69+62+75+⋯+77+7150=308250=61.64 Thus, the sample mean is 61.64.…

Q: Question # 5. The heights of men in Saudi Arabia are presumed to be normally distributed. You…

A: It is given that  Sample mean = 167 Population standard deviation = 7.5 Sample size = 150

Q: d with finding a 95% confidence interval for a population mean. You do not know the standard…

A: Confidence interval: It is defined as the range which contains the value of true population…

Q: 2. Again use the data from Table 4 [ Fifty randomly-selected Durham burials (1960-1969) ] . 90%…

A: Let X represents the Age of 50 randomly selected Durham burials between 1960 to 1969.         X…

Q: The weight (in lb) of widgets produced in a factory is normally distributed. A random sample of 9…

A: Since the sample size is n=9, the t-distribution should be used for constructing the confidence…

Q: Suppose you randomly sample 25 cans and find the mean amount of Coke in this sample is 11.85 ounces…

A: As per our guidelines I can solve only first three subparts. Kindly post the remaining subpart again…

Q: the analysis of a sample for iron content yields a mean result of 35.40% with standard deviation of…

A: Solution

Q: Question 16

A: It is an important part of statistics. It is widely used.

Q: The mean diastolic blood pressure for a random sample of 50 people was 86 millimeters of mercury. If…

A: Given that  Random sample size (n) = 50 Mean diastolic blood pressure (x¯) = 86 mmHg Standard…

Q: The mean diastolic blood pressure for a random sample of 80 people was 100 millimeters of mercury.…

A: Given  mean (x̄)  = 100 sample size (n)=80 standard deviation (s) =10 degree of freedom = df = n -1…

Q: 6. A sample of 15 students was used to estimate the performance of graduates of a certain college on…

A: Given : A sample of 15 student's was used to estimate the performance of graduates of a certain…

Q: A test had 12 items. A new version of a test was made by adding a set of 12 items which resembles…

A: Given : Total mean (μT)=18Total standard deviation(σT)=6True standard deviation (σt)=3