You intend to estimate a population mean u with the following sample. 59.2 68.9 68.3 63.3 113.1 56 61 You believe the population is normally distributed. Find the 99% confidence interval. Enter your answer as an open-interval (i.e., parentheses) accurate to twp decimal places (because the sample data are reported accurate to one decimal place). 99% C.I. = Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places.

Tina catches a 14-pound bass.  She does not know the population mean or standard deviation.  So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds.  Find the t and calculate a 95% (α = .05) confidence interval.

You are given the sample mean and the population standard deviation. Use this information to construct the​ 90% and​ 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If​ convenient, use technology to construct the confidence intervals. A random sample of 45 home theater systems has a mean price of ​$114.00. Assume the population standard deviation is ​$15.30. Construct a​ 90% confidence interval for the population mean.

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You intend to estimate a population mean u with the following sample. 95.6 77.1 72.5 83.2 81.1 72.3 73.4 63.1 You believe the population is normally distributed. Find the 99.5% confidence interval. Enter your answer as an open-interval (i.e., parentheses) accurate to twp decimal places (because the sample data are reported accurate to one decimal place). 99.5% C.I. = Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places. Submit Question Ce Ol 96 & 3. 00 27 %23

9 The standard error of the mean is, a 0.881       b 0.735       c 0.612       d 0.510

You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals. A random sample of 40 home theater systems has a mean price of $130.00. Assume the population standard deviation is $18.50. The 90% confidence interval is ( 125.19), 134.81). (Round to two decimal places as needed.) Construct a 95% confidence interval for the population mean. The 95% confidence interval is ( 124.27 , 135.73). (Round to two decimal places as needed.) Interpret the results. Choose the correct answer below. O A. With 90% confidence, it can be said that the population mean price lies in the first interval. With 95% confidence, it can be said that the population mean price lies in the second interval. The 95% confidence interval is narrower than the 90%. O B. With 90%…

You are given the sample mean and the population standard deviation. Use this information to construct the​ 90% and​ 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If​ convenient, use technology to construct the confidence intervals.   10. A random sample of 40 home theater systems has a mean price of ​$126.00. Assume the population standard deviation is ​$16.70. Construct a​ 90% confidence interval for the population mean.   The​ 90% confidence interval is ​(nothing​,nothing​)

Researchers studied the mean egg length (in millimeters) for a bird population. After taking a random sample of eggs, they obtained a 95% confidence interval of (45,60). What is the value of the margin of error? Choose the correct answer below. A. 15 mm B. 52.5 mm O c. 7.5 mm O D. 1.96

please round the answer to thousandth place. the other person did hundredths so It was incorrect