you help us make a program tracing in paper? Thank you!
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can you help us make a program tracing in paper? Thank you! <3
*The attached images are the code and the output.
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Solved in 2 steps with 4 images
- main.cpp:4:17: error: 'string' has not been declared 4 | void KMPSearch(string pat, string txt) main.cpp:4:29: error: string' has not been declared 4 | void KMPSearch(string pat, string txt) Aununun main.cpp:31:25: error: string' has not been declared 31 | void computelPSArray(string pat, int M, int[] lps) main.cpp:31:50: error: expected or . before lps' 31 | void computeLlPSArray(string pat, int M, int[] lps) main.cpp:55:8: error: expected :' before 'static' 55 | public static void Main() main.cpp:61:2: error: expected ;' after class definition 61 | } | main.cpp: In member function 'void GFG::KMPSearch(int, int)': main.cpp:6:15: error: request for member Length' in 'pat', which is of non-class type 'int' 6 | int M = pat.Length; main.cpp:7:15: error: request for member Length' in txt’, which is of non-class type 'int' int N = txt.Length; main.cpp:8:6: warning: structured bindings only available with -std3c++17' or (-std=gnu++17' 8 | int[] lps new int[M];public class Soru2 { static void sort(char a[]) { for(int i = 0; i < a.length; i++) { for(int j = i + 1; j < a.length; j++) { if(a[j] == 'X' && a[i] == 'O') { char temp = a[j]; a[j]=a[i]; a[i]=temp; } } } for(int i = 0; i < a.length; i++) { System.out.print(a[i] + " "); } } public static void main(String[] args) { char a[] = {'X','O','X','O','X','O','X','O','X','O'}; sort(a); } } Calculate the time complexity and number of steps of the algorithm?public class ArrayMerge { static void arrayMerge(int a[], int b[]){ int c[] = new int[50]; int k = 0; for(int i = 0; i < a.length; i++) { c[k++] = a[i]; } for(int i = 0; i < b.length; i++) { c[k++] = b[i]; } for(int i = 0; i < k; i++) { System.out.println(c[i]); } } public static void main(String[] args) { int a[] = { 18, 36, 41, 78, 56 }; int b[] = { 10, 37, 44 }; arrayMerge(a,b); } } Calculate the algorithm step number and algorithm time complexity of the above program?
- int main() //default function for call { int a[100],n,i,j; for (int i = 0; i < n; i++) //Loop for ascending ordering { for (int j = 0; j < n; j++) //Loop for comparing other values { if (a[j] > a[i]) //Comparing other array elements { int tmp = a[i]; //Using temporary variable for storing last value a[i] = a[j]; //replacing value a[j] = tmp; //storing last value } } } printf("\n\nAscending : "); //Printing message for (int i = 0; i < n; i++) //Loop for printing array data after sorting { printf(" %d ", a[i]); } } Need to transform this C code to MIPS Assembly Language Code simple stepsthe code: class HighArray { private long[] a; private int nElems; public HighArray(int max) { a = new long[max]; nElems = 0; } public void insert(long value) { a[nElems] = value; nElems++; } public boolean find(long searchKey) { int j; for (j = 0; j < nElems; j++) if (a[j] == searchKey) break; if (j == nElems) return false; else return true; } public long getMax() { if (nElems == 0) return 01; else { long max = a[0]; for (int i = 1; i < nElems; i++) { if (a[i] > max) max = a[i]; } return max; } } public boolean delete(long value) { int j; for (j = 0; j < nElems; j++) if (value == a[j]) break; if (j == nElems) return false; else { for (int k = j; k < nElems; k++) a[k] = a[k + 1]; nElems--; return true; } } public void display() { for (int j = 0; j < nElems; j++) System.out.print(a[j] + " "); System.out.println(""); }} public class HighArrayApp { public static void main(String[] args) { int maxSize =…const int size =4; int r1[size]; int i; for (i=0;i<2;i++) r1[i]= 2 * i+3; r1[3]=2 * i+ i; r1[2]=r1[3]; for (i=0;i1 int[] a = new int[n]; 2 a[0] = 0; a[1] = 1; 3 int x = 0; 4 for (int i = 2; i < n; i++) { 5 x = 3 * (i-1) * (i-1); 6 x += 3 * i - 2; 7 a[i] = a[i-1] + x; 8 } The code can be simplified by replacing lines 5, 6, 7 with a single line of code. Write the single line of code below:#include using namespace std; class Student { public: void setMarks(){ } double getAV(double a[]){ double sum=0; for(int i=0;i<7;i++) sum-sum+a[i]; return sum/7; double a[]={10, 20, 30, 40, 50, 60, 70); cout<2D-DP-3 int getLowestFromArray(int myList[], int size) int i; int lowestIndex = 0; for (i = 1; i myList[i]) lowestIndex = i; return lowestIndex; int main() int cData[2][5] = {{12, 5, 4, 7, 8}, {6, 35, 3, 27, 8}}; int i, lowest; for (i = 0; i < 2; i++) lowest = printf("%d\n", lowest); return 0; Given the code segment above, what will be needed to complete the code above? Assume the necessary libraries and functions are included and implemented. Encoding Instructions: Write your answers with NO SPACES. Answers not accepted by automatic checking in AnimoSpace due to not complying with the encoding instructions will not be given considerations.Course: Data Structure and Algorithms Language: C++ Question is well explained Question #2Implement a class for Circular Doubly Linked List (with a dummy header node) which stores integers in unsorted order. Your class definitions should look like as shown below: class CDLinkedList;class DNode {friend class CDLinkedList;private int data;private DNode next;private DNode prev;};class CDLinkedList {private:DNode head; // Dummy header nodepublic CDLinkedList(); // Default constructorpublic bool insert (int val); public bool removeSecondLastValue (); public void findMiddleValue(); public void display(); };int a[10] = {0,1,2,3,4,5,6,7,8,9};int *m = &a[0];int *p = &a[5];int *q = &a[1]; p = (int) m + (int) p - (int) q; what is the value of of *p12.14 Zylab 3 - Single Procedure Call Given an array of at least one integer, write a program to create a new array with elements equal to the power of each element in the original array raised to the index, i.e., P[i] = A[i]^i. For this, write two functions that will be called in main function independently. ● power inputs: element (A[i]) and index (1) • task: returns the value of element raised to index (A[i]^i). } O • newElement inputs: base address of new array P (*P), current size of P (variable k) and the new element (A[i]^i) o task: add the new element at the end. o This function does not return any value (void). O Following is a sample C code to perform the required task. You may modify the code for the functions, but the task performed should not be changed. int main() { // Variable Declaration int *A, *P; int n, k; int pow; // Task of main function P[0] 1; for (int j = k = j; pow // Base addresses of A and P // Lengths of arrays A and B // Return value from power function }…SEE MORE QUESTIONSRecommended textbooks for youDatabase System ConceptsComputer ScienceISBN:9780078022159Author:Abraham Silberschatz Professor, Henry F. Korth, S. 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