You have a light spring which obeys Hooke's law. This spring stretches 3.28 cm vertically when a 2.70 kg object is suspended from it. Determine the following. (a) the force constant of the spring (in N/m) N/m (b) the distance (in cm) the spring stretches if you replace the 2.70 kg object with a 1.35 kg object cm (c) the amount of work (in J) an external agent must do to stretch the spring 7.70 cm from its unstretched position J

Q: A 0.500 kg mass is hung from a vertical spring which then stretches by 10.5 cm. (a) What is the…

A: Given: Mass m=0.500 kg Elongation  y=10.5 cm=10.5×10-2 m Mass m1=1.25 kg

Q: A ride at an amusement park attaches people to a bungee cord, pulls them straight down to the…

A: Given data: Spring stiffness constant is, k=35 N/m. Height beyond the unloaded length is, h=100 m.…

Q: 3. Three springs are connected in a series (head to toe) and an 867.6g mass is suspended from the…

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Q: Why does Hooke's law have a negative sign? the spring force is a friction force the spring force…

A: Given : Why does Hooke's law have a negative sign? the spring force is a friction force the spring…

Q: 1. ssm A hand exerciser utilizes a coiled spring. A force of 89.0 N is required to compress the…

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Q: A certain spring is known to obey Hooke's Law. If a force of 10 newtons stretches the spring 2…

A: The expression for the Hooke’s law is given as,

Q: If a spring is stretched 4.50 cm by a suspended object having a mass of 0.83 kg, what is the force…

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Q: You have a light spring which obeys Hooke's law. This spring stretches 3.22 cm vertically when a…

A: Given data: The mass is m = 2.00 kg The displacement in the spring is x =3.22 cm (a) The force…

Q: You have a light spring which obeys Hooke's law. This spring stretches 3.20 cm vertically when a…

A: stretch = 3.2 cm  mass, m= 2.7 kg  Let the force constant is K.   F = m g = K y (2.7)(9.8) = K…

Q: Review Conceptual Example 2 as an aid in solving this problem. An object is attached to the lower…

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Q: What is the spring constant of a spring scale that stretches 1.5 cm when a basket of vegetables of…

A: Spring stretch (x) = 1.5 cm = 1.5 × 10^-2 m  Mass of the basket (m) = 0.25 kg  Let spring constant…

Q: What is the tension in cable AB? FAB = 100 N. . FAc = 120 N FaC 4 m 4 m CO 2 m (480î + 240ĵ – 480k)N

A: Given, The magnitude of forces in the cable which are holding a plate

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Q: You have a light spring which obeys Hooke's law. This spring stretches 2.34 cm vertically when a…

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Q: A spring is stretched vertically by 0.50 meters when a 15 kg mass is hung from the spring and the…

A: mass = 15 kg stretching in spring = 0.5 m

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A: Given   Spring constant of bungee cord , k= 112 N/m Mass hung to it m = 50.0 kg To find  The…

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Q: When a 2.90-kg object is hung vertically on a certain light spring described by Hooke's law, the…

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Q: When a 4.70-kg object is hung vertically on a certain light spring that obeys Hooke's law, the…

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Q: How do I determine the proportional constant of a mass hanging from a spring when I am give the…

A: ∆L=0.0704 mg    =9.8 m/s2And F=K(∆L)=(0.0704)KAndMg=(9.8)M

Q: A frictionless spring with a 8-kg mass can be held stretched 1.2 meters beyond its natural length by…

A: Solution: The restoring force applied by the spring is 100N and a retarding force equal to twice its…

Q: 10. A 75.0-kg circus performer jumps from a height 4.90 m onto a trampoline and it stretches 0.35 m.…

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Q: 11. A 0.37 kg ball is suspended from a vertical spring with spring constant of 100.0 N/m. What is…

A: The ball of mass 0.37 kg is suspended vertically from a spring of spring constant 100 N/m m=0.37…

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Q: When a 2.90-kg object is hung vertically on a certain light spring described by Hooke's law, the…

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Q: P6

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Spring Potential Energy

The potential energy is the energy possessed by a body by virtue of its position or the energy held by the object due to its position relative to other objects, its force like stresses, charge, and other factors affecting the particles of the body. The potential energy is the measure of the net work done by or on the body. The spring potential energy is the potential energy stored due to the deformation of an elastic spring and this elasticity is due to the stretched spring. The elasticity is the ability of a solid-state matter to come back to its equilibrium position or original position after any kind of external force is acted on it. It is also known as Elastic potential energy. The potential energy here is caused due to the displacement of the spring from its equilibrium position to another position and this potential energy is equal to the net work done due to the stretching of the spring. It also resembles the same mechanics of the oscillation of a simple pendulum, where due to the external force, the object moves from its equilibrium position to its maximum ends and the periodic motion continues till it comes back to the equilibrium position to rest.