You hang a 1.0 kg mass from a spring scale. But this time, instead of holding your hand still so that the acceleration is zero, you let your arm drop so that the mass accelerates downward at 5.2 m/s2. What force (how many Newtons) will the spring scale read while this acceleration is happening assuming that you are standing on the surface of Earth, so that the force on the 1.0 kg mass due to gravity is 9.8 Newtons?

A flea jumps by exerting a force of 1.17 x 10-5 N straight down on the ground. A breeze blowing on the flea parallel to the ground exerts a force of 1.12 x 10-6 N on the flea. Find the direction and magnitude (in m/s²) of the acceleration of the flea if its mass is 6.0 × 10-7 kg. (Let us assume that wind points to the right. We will consider this to be the +x direction and vertical to be the +y direction.) magnitude direction m/s² ° (measured clockwise from the vertical)

You are standing on a bathroom scale in an elevator (yes people are staring at you).  You weigh 50 kg but the scale reads in Newtons. Weight (force of Gravity) = Mass x Gravity (10m/s2) As the elevator comes up on the ground floor it decelerates at 2 m/s2 downward.    What is the Gravitational Force?     Since the elevator is decelerating downward does the Normal Force have to be greater than, equal to or less than the Force of Gravity?     Are the forces balanced or unbalanced?     Draw a free body diagram of the forces acting on you.  Be sure to draw the size of your arrows appropriately.     What is the Net Force, using Newton’s 2nd Law, while the elevator is decelerating downward?     What is the Normal Force?     What does the scale read as the elevator is decelerating downward?     What pattern did you notice occurred between all of the different scenarios?

You are trying to escape a hoard of zombies and must make an elevator to get down a cliff as fast as possible.  As you cannot hit the ground faster than 10m/s and the cliff is 25m deep, this limits your acceleration to 2 m/s2 (you will want to accelerate at this rate to get down the cliff as fast as you can).  Assuming your and the bucket’s mass together is 100kg (m2) , what is the minimum mass (m1) that the sled must be to prevent your death (assume the ground is frictionless).

3. A 2.0 kg mass moving in space according to v = (6.0t² + 1.0)î + (7.0t²)j + (t³)k (relative to the origin), with v in meter/second and t in seconds. At t =1 s (a) what are the magnitude and direction of the force acting on the mass relative to the x-axis (b) what is the angle between the acceleration and velocity vector (c) what are the magnitude and direction of the average velocity? (d) What is the mass angular momentum vector relative to the origin? (e) What is the torque vector acting on the mass relative to the origin? (f) WWhat is the work done by this force from t = 0 s tot = 1.0 s? (g) What is the instantaneous power at t = 1.0 s.

A skydiver weighing 178 lbf (including equipment) falls vertically downward from an altitude of 5000 ft and opens the parachute after 17s of free fall. Assume that the force of air resistance, which is directed opposite to the velocity, is 0.76 |v| when the parachute is closed and 12 |v| when the parachute is open, where the velocity v is measured in ft/s. Use g = 32 ft/s². Round your answers to two decimal places. (a) Find the speed of the skydiver when the parachute opens. v(17) = i ft/s (b) Find the distance fallen before the parachute opens. x(17) = i ft (c) What is the limiting velocity v after the parachute opens? VL = i ft/s

A small 930 kg rocket applies its thrusters from rest to generate a net force of F=2260t+2630 newtons, where tt is time. Assuming no air resistance, calculate the rocket's velocity, v, in m/s after 9 seconds.   Enter your answer for v in m/s, correct to three significant figures: ........  m/s

The gravitational acceleration in space is 0 m/s². Calculate the weight in Newtons of an average human woman (60 kg) in space? 9.8 N 686 N 1.625 N ON 70 N 113.75 N 43.08 N

v: Consider the following equation: GMm F (1) R2 a) Define the parameters in Equation 1. b) What does Equation 1 mean? c) Combine Equation 1 and Newton's second law of motion. What does the result tell you?

The gravitational acceleration on the moon is 1.625 m/s² . What would the weight be of an average human man (70 kg) on the moon in Newtons? 113.75 N 43.08 N 9.8 N 1.625 N 70 N 686 N ON