You drive a beat-up pickup truck along a straight road for 8.4 km at 70 km/h, at which point the truck runs out of gaso- line and stops. Over the next 30 min, you walk another 2.0 km farther along the road to a gasoline station. (a) What is your overall displacement from the beginning of your drive to your arrival at the station?

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Chapter2: Kinematics
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Problem 21CQ: An object that is thrown straight up falls back to Earth. This is one-dimensional motion. (a) When...
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fundamentals-o...hysics-textbook - Read-only
chapi 1/ 222 X
Sample Problem 2.01 Average velocity, beat-up pickup truc
You drive a beat-up pickup truck along a straight road for
8.4 km at 70 km/h, at which point the truck runs out of gaso-
line and stops. Over the next 30 min, you walk another
2.0 km farther along the road to a gasoline station.
Calculation
(a) What is your overall displacement from the beginning
of your drive to your arrival at the station?
To find va
shown in F
the graph am
average ve
those point
to the run (
KEY IDEA
Assume, for convenience, that you move in the positive di-
rection of an x axis, from a first position of x, = 0 to a second
position of x2 at the station. That second position must be at
x2 = 8.4 km + 2.0 km = 10.4 km. Then your displacement Ax
along the x axis is the second position minus the first position.
(d) Suppo:
back to the
Calculation: From Eq. 2-1, we have
average sp
return to th
Ar = x2 - x, = 10.4 km – 0 = 10.4 km.
(Answer)
KEY IDE
Thus, your overall displacement is 10.4 km in the positive
direction of the x axis.
Your avera
(b) What is the time interval At from the beginning of your
drive to your arrival at the station?
move to th
Calculatio,
km = 12.4
KEY IDEA
0.75 h = 1.
We already know the walking time interval Atw (= 0.50 h),
but we lack the driving time interval Atgr. However, we
know that for the drive the displacement Ax4 is 8.4 km and
the average velocity vavg.dr is 70 km/h. Thus, this average
velocity is the ratio of the displacement for the drive to the
time interval for the drive.
Calculations: We first write
12
Ax dr
10
Vavg.dr =
Atar
Rearranging and substituting data then give us
Ardr
8.4 km
Att =
= 0.12 h.
Vavg.dr
70 km/h
So,
At = Att + Atwik
= 0.12 h + 0.50 h = 0.62 h.
(Answer)
(c) What is your average velocity vavg from the beginning of
your drive to your arrival at the station? Find it both numer-
ically and graphically.
Figure 2-5 Th
position-tim
for the walk
KEY IDEA
From Eq. 2-2 we know that vavg for the entire trip is the ratio
of the displacement of 10.4 km for the entire trip to the time
interval of 0.62 h for the entire trip.
slope of the
"Station" is
to the statio
Position (km)
...
Transcribed Image Text:1:12 fundamentals-o...hysics-textbook - Read-only chapi 1/ 222 X Sample Problem 2.01 Average velocity, beat-up pickup truc You drive a beat-up pickup truck along a straight road for 8.4 km at 70 km/h, at which point the truck runs out of gaso- line and stops. Over the next 30 min, you walk another 2.0 km farther along the road to a gasoline station. Calculation (a) What is your overall displacement from the beginning of your drive to your arrival at the station? To find va shown in F the graph am average ve those point to the run ( KEY IDEA Assume, for convenience, that you move in the positive di- rection of an x axis, from a first position of x, = 0 to a second position of x2 at the station. That second position must be at x2 = 8.4 km + 2.0 km = 10.4 km. Then your displacement Ax along the x axis is the second position minus the first position. (d) Suppo: back to the Calculation: From Eq. 2-1, we have average sp return to th Ar = x2 - x, = 10.4 km – 0 = 10.4 km. (Answer) KEY IDE Thus, your overall displacement is 10.4 km in the positive direction of the x axis. Your avera (b) What is the time interval At from the beginning of your drive to your arrival at the station? move to th Calculatio, km = 12.4 KEY IDEA 0.75 h = 1. We already know the walking time interval Atw (= 0.50 h), but we lack the driving time interval Atgr. However, we know that for the drive the displacement Ax4 is 8.4 km and the average velocity vavg.dr is 70 km/h. Thus, this average velocity is the ratio of the displacement for the drive to the time interval for the drive. Calculations: We first write 12 Ax dr 10 Vavg.dr = Atar Rearranging and substituting data then give us Ardr 8.4 km Att = = 0.12 h. Vavg.dr 70 km/h So, At = Att + Atwik = 0.12 h + 0.50 h = 0.62 h. (Answer) (c) What is your average velocity vavg from the beginning of your drive to your arrival at the station? Find it both numer- ically and graphically. Figure 2-5 Th position-tim for the walk KEY IDEA From Eq. 2-2 we know that vavg for the entire trip is the ratio of the displacement of 10.4 km for the entire trip to the time interval of 0.62 h for the entire trip. slope of the "Station" is to the statio Position (km) ...
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