You charge an initially uncharged 69.1 mF capacitor through a 24.9 2 resistor by means of a 9.00 V battery having negligible internal resistance. Find the time constant t of the circuit. T = S What is the charge Q on the capacitor 1.25 time constants after the circuit is closed? Q = What is the charge Qo after a long amount of time has passed? Qo =

E2 R1 R2 2. Find the charge on the capacitor after the switch has been left open for some time, then closed for some period of time. We can assume that C = 2 µF, with batteries of values E1 R2 = 0.25 N. 2V and E2 =1V, and resistor values R1 = 0.5 N and S

3. A 3 μF capacitor initially has a voltage of 1.5 V when it is discharged through a resistance R. The voltage 3 ms after it has started to discharge is 0.25 Volts. Determine the time constant Tc. a. b. Determine the resistance R.

Four capacitors are arranged in the circuit shown in the figure. The capacitors have the values C₁ = 24.5 µF, C₂ = 45.5 µF, C3 = 50.5 µF, and C4 = 40.5 µF, and the power supply is at voltage V = 26.5 V. What is the equivalent capacitance of the circuit? equivalent capacitance: What is the charge on capacitor C₂? charge on C₂: What is the potential difference across capacitor C3? potential difference across C3: What is the potential energy stored in capacitor C4? potential energy stored in C4: HF с V J V C3 C₁ C₂ C₁

The shown circuit has been closed for a long time. Find the charge (in uC) on the 6 uF capacitor if ɛ=11 V. 6µF 50 2µF

Consider the circuit shown in the figure. A short time after closing the switch, the charge on the capacitor is 90.0% of its initial charge. Assume the circuit has a time constant of 17.7 s. +Q (a) Calculate the time interval required (in s) for the capacitor to reach this charge. (b) If R = 220 k2, what is the value of C (in uF)? µF Need Help? Read It