You build a shelf by putting a 0.90 m board across two supports. One support is at the left end of the board and the other is 0.10 m from the right end. The board has a mass of 1.25 kg and you place a potted plant with a mass of 3.40 kg, 0.65 m from the left end of the board.

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### Physics Problem: Shelf with Supports and Weight Distribution

---

#### Problem Statement:
You build a shelf by putting a 0.90 m board across two supports. One support is at the left end of the board and the other is 0.10 m from the right end. The board has a mass of 1.25 kg and you place a potted plant with a mass of 3.40 kg, 0.65 m from the left end of the board.

#### Diagram Explanation:
The diagram shows a horizontal board positioned across two vertical supports. Specific measurements and masses are marked on the diagram as follows:

- **Board Length:** 0.90 m
- **Left Support Position:** At the left end of the board (0 m mark)
- **Right Support Position:** 0.10 m from the right end of the board
- **Mass of the Board (m):** 1.25 kg centered along its length
- **Mass of the Potted Plant (m):** 3.40 kg located 0.65 m from the left end of the board

The board and potted plant are shown with arrows indicating the positions and distances from the left end of the board.

#### Tasks:
a. Draw a free-body diagram labeling all the forces and distances. Also, choose and mark a pivot point for your shelf on the drawing.

b. Find the force exerted by both supports.

---
### Physics Concepts Involved:

- **Torque and Equilibrium:** Utilize principles of torque and static equilibrium to solve for the forces at the supports.
- **Free-Body Diagram (FBD):** A graphical illustration used to visualize the applied forces, moments, and reactions on a body.

To solve the problem:

1. **Determine the Pivot Point:**
    - Typically, one support or the center of mass of the system can be used as a pivot.

2. **Calculate Forces:**
    - Apply the equilibrium condition for both forces and torques:
        - ΣF = 0 (sum of vertical forces must be zero)
        - Στ = 0 (sum of torques around any point must be zero)

3. **Equations:**
    - For instance, if taking the left support as the pivot,
        - Consider the torque due to the board’s weight and the plant’s weight about the left support.

   - Calculate individual contributions to the net torque to find the unknown forces.

Use these principles
Transcribed Image Text:### Physics Problem: Shelf with Supports and Weight Distribution --- #### Problem Statement: You build a shelf by putting a 0.90 m board across two supports. One support is at the left end of the board and the other is 0.10 m from the right end. The board has a mass of 1.25 kg and you place a potted plant with a mass of 3.40 kg, 0.65 m from the left end of the board. #### Diagram Explanation: The diagram shows a horizontal board positioned across two vertical supports. Specific measurements and masses are marked on the diagram as follows: - **Board Length:** 0.90 m - **Left Support Position:** At the left end of the board (0 m mark) - **Right Support Position:** 0.10 m from the right end of the board - **Mass of the Board (m):** 1.25 kg centered along its length - **Mass of the Potted Plant (m):** 3.40 kg located 0.65 m from the left end of the board The board and potted plant are shown with arrows indicating the positions and distances from the left end of the board. #### Tasks: a. Draw a free-body diagram labeling all the forces and distances. Also, choose and mark a pivot point for your shelf on the drawing. b. Find the force exerted by both supports. --- ### Physics Concepts Involved: - **Torque and Equilibrium:** Utilize principles of torque and static equilibrium to solve for the forces at the supports. - **Free-Body Diagram (FBD):** A graphical illustration used to visualize the applied forces, moments, and reactions on a body. To solve the problem: 1. **Determine the Pivot Point:** - Typically, one support or the center of mass of the system can be used as a pivot. 2. **Calculate Forces:** - Apply the equilibrium condition for both forces and torques: - ΣF = 0 (sum of vertical forces must be zero) - Στ = 0 (sum of torques around any point must be zero) 3. **Equations:** - For instance, if taking the left support as the pivot, - Consider the torque due to the board’s weight and the plant’s weight about the left support. - Calculate individual contributions to the net torque to find the unknown forces. Use these principles
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