
Database System Concepts
7th Edition
ISBN: 9780078022159
Author: Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher: McGraw-Hill Education
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
You are writing a query about hospital encounters using the following FROM clause:
FROM PAT_ENC HSP peh
<join type> CLARITY_DEP dep ON peh.DEPARTMENT_ID = dep.DEPARTMENT_ID
DEPARTMENT_ID is never NULL in either table, and for every DEPARTMENT_ID in PAT_ENC_HSP, there is a matching DEPARTMENT_ID in CLARITY_DEP. Assuming no additional filtering, which join type must you use?
A. You must use either an INNER JOIN or a LEFT OUTER JOIN, and either would return the same results
B. You must use an INNER JOIN
C. You must use a LEFT OUTER JOIN
D. You must use a CROSS JOIN
Expert Solution

This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution
Trending nowThis is a popular solution!
Step by stepSolved in 3 steps

Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, computer-science and related others by exploring similar questions and additional content below.Similar questions
- Emp:- Id is Primary keyProject:- EmpId foreign key.Find out the output of the left outer join, right outer join and inner join.Take the below columns in output:-Emp table ID, name.Project table projectID, NAMEarrow_forwardJOIN TABLES One row in the PAT_ENC table represents one patient encounter. One row in the ORDER MED table represents one medication order. One patient encounter can have many medication orders but one medication order can only have one patient encounter. In other words, the cardinality of this PAT_ENC to ORDER_MED relationship is one-to- many. You start a query with PAT_ENC. You then add ORDER_MED using an inner join. What is true about the granularity of the result set before and after adding the ORDER_MED table? SELECT ONE OF THE FOLLOWING A. The granularity stays at one row per patient encounter. B. The granularity stays at one row per medication order. C. The granularity changes from one row per patient encounter to one row per medication order on an encounter. D. The granularity changes from one row per medication order to one row per patient encounter.arrow_forwardThe PA T_ENC_HSP table has 100 rows each, representing the hospital and counter. The ADMISSION _PROV_ID column identifies encounters admitting provider. There are five unique known values in ADMISSION _PROV_ID and separately, there are encounters with a null admitting provider. Use the following query to answer the question below: Select ADMISSION _PROV_ID FROM PAT_ENC_HSP GROUP BY ADMISSION_PROV_ID How many rows will be in the results? Select one of the following:A. 0 B. 5 C . 6 D. 100 E. 500arrow_forward
- A Cartesian join between a table with 5 records and a table with 10 records returns how many rows?arrow_forwardMy SQL WORKBENCH **Please note that you may actually use as many tables as you need. You are not limited to use only twotables.Example:SELECT *FROM DEPARTMENTS;SELECT *FROM EMPLOYEES;Now join departments and employees tables.SELECT FIRST_NAME, DEPARTMENT_NAMEFROM EMPLOYEES, DEPARTMENTSWHERE EMPLOYEES.DEPARTMENT_ID = DEPARTMENTS.DEPARTMENT_ID;NOTE: If you omit the join condition, the result will be the Cartesian Product of the two tables. A CartesianProduct joins all rows of the first table with all rows of the second table.That is if the first table has n rows and the second table has m rows, the output will have n*m rows.The following query will produce a Cartesian Product:SELECT FIRST_NAME, DEPARTMENT_NAMEFROM EMPLOYEES, DEPARTMENTS;**When table names are long, qualifying column names might be very time consuming. Usually peopleprefer to use table aliases for this purpose.Example: List the name of all employees who work for 'Purchasing' departmentSELECT E.FIRST_NAME "EMPLOYEE…arrow_forward
arrow_back_ios
arrow_forward_ios
Recommended textbooks for you
- Database System ConceptsComputer ScienceISBN:9780078022159Author:Abraham Silberschatz Professor, Henry F. Korth, S. SudarshanPublisher:McGraw-Hill EducationStarting Out with Python (4th Edition)Computer ScienceISBN:9780134444321Author:Tony GaddisPublisher:PEARSONDigital Fundamentals (11th Edition)Computer ScienceISBN:9780132737968Author:Thomas L. FloydPublisher:PEARSON
- C How to Program (8th Edition)Computer ScienceISBN:9780133976892Author:Paul J. Deitel, Harvey DeitelPublisher:PEARSONDatabase Systems: Design, Implementation, & Manag...Computer ScienceISBN:9781337627900Author:Carlos Coronel, Steven MorrisPublisher:Cengage LearningProgrammable Logic ControllersComputer ScienceISBN:9780073373843Author:Frank D. PetruzellaPublisher:McGraw-Hill Education

Database System Concepts
Computer Science
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:McGraw-Hill Education

Starting Out with Python (4th Edition)
Computer Science
ISBN:9780134444321
Author:Tony Gaddis
Publisher:PEARSON

Digital Fundamentals (11th Edition)
Computer Science
ISBN:9780132737968
Author:Thomas L. Floyd
Publisher:PEARSON

C How to Program (8th Edition)
Computer Science
ISBN:9780133976892
Author:Paul J. Deitel, Harvey Deitel
Publisher:PEARSON

Database Systems: Design, Implementation, & Manag...
Computer Science
ISBN:9781337627900
Author:Carlos Coronel, Steven Morris
Publisher:Cengage Learning

Programmable Logic Controllers
Computer Science
ISBN:9780073373843
Author:Frank D. Petruzella
Publisher:McGraw-Hill Education