You are working with your friends Alice and Bob on your Calculus homework. While you were away running an errand, they computed the integral / 2 sinxcosxdx, but they cannot agree on the correct answer. Alice made the substitution u = sinx with du= cosxdx, and then wrote: 2 sinxcosxdx= 2 sinx(cos.xdx) = 2udu %3 u? +С 3 sin? x +C. Bob made the substitution u = cosx with du =- sinxdx, and then wrote: 2 sinxcos.xdx = /: 2 cosx (sinxdx) 2u (-du) — — и? +С%3- сos? х+С. = Did one of your friends make a mistake? If yes, who made a mistake and where is the mistake? If you think neither of them made a mistake, then address their concern:“How can you have two different-looking correct answers for the same integral"?

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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3. You are working with your friends Alice and Bob on your Calculus homework. While you were away running
an errand, they computed the integral / 2 sinxcosxdx, but they cannot agree on the correct answer.
Alice made the substitution u =
sinx with du = cosxdx, and then wrote:
2 sinxcosxdx = | 2 sinx(cos.xdx) = / 2udu = u? +C = sin?x+C.
Bob made the substitution u = cosx with du = – sinxdx, and then wrote:
2 sinxcosxdx = | 2cosx (sinxdx) = | 2u(-du) = -ư² +C=- cos?x+C.
Did one of your friends make a mistake? If yes, who made a mistake and where is the mistake? If you think
neither of them made a mistake, then address their concern:"How can you have two different-looking correct
answers for the same integral"?
Transcribed Image Text:3. You are working with your friends Alice and Bob on your Calculus homework. While you were away running an errand, they computed the integral / 2 sinxcosxdx, but they cannot agree on the correct answer. Alice made the substitution u = sinx with du = cosxdx, and then wrote: 2 sinxcosxdx = | 2 sinx(cos.xdx) = / 2udu = u? +C = sin?x+C. Bob made the substitution u = cosx with du = – sinxdx, and then wrote: 2 sinxcosxdx = | 2cosx (sinxdx) = | 2u(-du) = -ư² +C=- cos?x+C. Did one of your friends make a mistake? If yes, who made a mistake and where is the mistake? If you think neither of them made a mistake, then address their concern:"How can you have two different-looking correct answers for the same integral"?
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