You are saying that the inhibitor is competitive inhibitor. But according to data Vmax for reaction (with no inhibitor) is 4,17mM/min and Vmax for reaction (with inhibitor)=2,31mM/min. Then you show that Km for reaction with no inhibitor is 1.66. Then I calculate further for Km for reaction with inhibitor by using MM equation and I get 0,9. So both the Vmax and Km is reduced in reaction with inhibitor. That must mean the inhibitor is not competitive but non-competitive inhibitor. Or is it me that got it wrong??
Enzyme kinetics
In biochemistry, enzymes are proteins that act as biological catalysts. Catalysis is the addition of a catalyst to a chemical reaction to speed up the pace of the reaction. Catalysis can be categorized as either homogeneous or heterogeneous, depending on whether the catalysts are distributed in the same phase as that of the reactants. Enzymes are an essential part of the cell because, without them, many organic processes would slow down and thus will affect the processes that are important for cell survival and sustenance.
Regulation of Enzymes
A substance that acts as a catalyst to regulate the reaction rate in the living organism's metabolic pathways without itself getting altered is an enzyme. Most of the biological reactions and metabolic pathways in the living systems are carried out by enzymes. They are specific for their works and work in particular conditions. It maintains the best possible rate of reaction in the most stable state. The enzymes have distinct properties as they can proceed with the reaction in any direction, their particular binding sites, pH specificity, temperature specificity required in very few amounts.
You are saying that the inhibitor is competitive inhibitor. But according to data Vmax for reaction (with no inhibitor) is 4,17mM/min and Vmax for reaction (with inhibitor)=2,31mM/min.
Then you show that Km for reaction with no inhibitor is 1.66.
Then I calculate further for Km for reaction with inhibitor by using MM equation and I get 0,9.
So both the Vmax and Km is reduced in reaction with inhibitor. That must mean the inhibitor is not competitive but non-competitive inhibitor. Or is it me that got it wrong??
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