You are part of a team studying the length of time that people who have had the Covid-19 virus continue to experience lingering symptoms. A survey of 32 randomly chosen individuals reveals that the mean length of time that symptoms lingered was 49 days, with a sample standard deviation of 10.2 days. Find a 98% confidence interval for the true length of time that Covid-19 virus symptoms linger. What is the point estimate for this interval? ________________ What is the margin of error for this interval? _________________ (2 decimals) Give the confidence interval: (______________,_______________)

Q: A random sample of 20 students yielded a mean of 68,55 and a standard deviation of 4,59 for scores…

A: The question is about confidence interval Given : Randomly selected no. of students ( n ) = 20…

Q: A random sample of 64 business students required an average of 100 minutes to complete a statistics…

A: Given that, Mean = 100 Standard deviation = 20 Sample size = 64 95% confidence level

Q: You measure 21 watermelons' weights, and find they have a mean weight of 47 ounces. Assume the…

A: sample size (n)=21Mean()=47standard deviation()=5.6confidence level=90%

Q: You are part of a team studying the length of time that people who have had the Covid-19 virus…

A:

Q: A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…

A:

Q: You measure 31 turtles' weights, and find they have a mean weight of 59 ounces. Assume the…

A:

Q: You measure 29 turtles' weights, and find they have a mean weight of 44 ounces. Assume the…

A:

Q: A sample of n = 43 data values randomly selected from a normally distributed population has varlance…

A: Degrees of freedom = n-1=43-1=42 (by using the standard normal table)

Q: For a sample 1000 app users, the research team reports an average age of 39. If the population…

A: given data  n = 1000 x¯ = 39σ = 9.590% ci, upper bound of ci  = ?

Q: In a sample of 80 light bulbs, the mean lifetime was 1,217 hours with a standard deviation of 52.0…

A: Given information :Mean(xˉ)=1217σ=52n=80Step 2:The margin of error calculated by the…

Q: A random sample of 12 chemists from Washington stats shows an average salary of $39,420 with a…

A: The sample mean one (Washington): x¯1=$39,420, sample mean two (New Mexico): x¯2=$30,215, population…

Q: people who had a certain subtype of influenza A at The General Hospital in the last month. For this…

A: Given that  Sample size n =100 Sample mean=8.6 Standard deviation =3.3

Q: Suppose we are interested in a confidence interval for the population mean scores on an exam. A…

A: We have given that,  Sample mean (x̄) = 107.65, population standard deviation (σ) = 4.72 Then,  We…

Q: You are a researcher studying the lifespan of a certain species of bacteria. A preliminary sample of…

A: Solution: Given data: Preliminary Sample size = 40 Sample mean = 72 Standard deviation  = 6.4 Margin…

Q: sample standard deviation of $74.50. a. Develop a  95% confidence interval estimate of the mean…

A: The sample size, i.e., the sampled number of families, n=64.The sample average spent amount(in $)…

Q: A comparison between species: Biologists comparing the gestation period of two newly discovered…

A: a) Denote μA, μB as the true average gestation period of frogs of species A and Species B,…

Q: of frog collected data from 13 frogs of species A and 24 frogs of species B. Species A exhibited an…

A:

Q: You measure the blackbody temperature of the night sky three times and read: 7.3C, 9.1C, and 8.7C.…

A: Given : 1.   Temperature f night sky(in  degree celcies)    : 7.3, 9.1, and 8.7. 2.   Sample  mean =…

Q: In a behavioral study of gibbons, it was found that their song duration X is a random variable which…

A: Given: X: Song duration (in minutes)

Q: A group of 65 randomly selected students have a mean score of 30.6 with a standard deviation of 5.4…

A:

Q: what is the maximal margin of error associated

A: You measure 26 watermelons' weights, and find they have a mean weight of 31 ounces. Assume the…

Q: A comparison between species: Biologists comparing the gestation period of two newly discovered…

A: (a) State the hypotheses. That is, there is no evidence that the average lengths of the gestation…

Q: A random sample of 20 students yielded a mean of 68,55 and a standard deviation of 4,59 for scores…

A: From the provided information, the followings are interpreted: The sample size, n=20. The sample…

Q: You measure 94 turtles' weights, and find they have a mean weight of 70 ounces with a standard…

A: You measure 94 turtles' weights, and find they have a mean weight of 70 ounces with a standard…

Q: A survey conducted by the American Automobile Association (AAA) showed that a family of four spends…

A: Given that: Population mean, μ=215.60 n = 64 x¯=252.45 s = 74.50

Q: Recent data from a national survey indicated that the average woman goes to a salon once every five…

A: We have given that the average woman goes to a salon once every five weeks and spend on average…

Q: In a survey, 5 people were asked how much they spent on their child's last birthday gift. The…

A:

Q: A researcher is interested in finding a 95% confidence interval for the mean number minutes students…

A: Given Information: Sample size (n) = 41  Mean (x) = 41.2 minutes Standard Deviation (s) = 12.3…

Q: Find a 90% confidence interval for the population mean age of the Smurfs if a sample of 52 smurfs…

A: It is given that, There is a random sample of size 52 and has a mean of 49.7 and the standard…

Q: the study, n = 52 men were put on a diet. The men who dieted lost an average of 6.0 kg, with a…

A: Given that ; Sample size (n) = 52 Sample mean = 6.0 kg  ? = 3.7  kg By using one sample mean test we…

Q: researcher is interested in finding a 95% confidence interval for the mean number Minutes students…

A:

Q: In an experimental study of the longevity of Drosophila melanogaster (fruit fly) 70 male adults and…

A: Solution: 1. State the hypotheses. Null hypothesis: That is, the male Drosophila not has a greater…

Q: One​ year, the mean age of an inmate on death row was 38.1years. A sociologist wondered whether the…

A:

Q: In a random sample of 41 criminals convicted of a certain​ crime, it was determined that the mean…

A:

Q: company manufactures a certain over-the-counter drug. The company samples 80 pills and finds that…

A: We have given that  Sample size n = 80 Sample mean = 325.5 Standard deviation s=10.3 90%confidence…

Q: You measure the blackbody temperature of the night sky three times and read: 7.3C, 9.1C, and 8.7C.…

A: Use the given data to form the excel table:   x x-μ x-μ2   7.3 -1.06667 1.1379…

Q: number

A: Given: Mean, x=3.5 Sample standard deviation, s=1.6 Sample size, n = 219 To compute the confidence…

Q: A sample of twenty newborn elephants had a sample mean of 225 pounds and a sample standard deviation…

A: Here, the population standard deviation is given. Hence, it will be best to use a z- interval.

Q: A survey conducted by the AAA showed that a family of four spends on average $215.60 per day while…

A: It is given that sample mean is 252.45 and the standard deviation is 74.50.

Q: A random sample of 50 roundtrip flights between New York and Chicago has an average airfare of $400…

A: Given : A random sample of 50 round-trip flights between New York and Chicago has an average airfare…

Q: Contstruct a 95% confidence interval for the population mean length of time that people have lived…

A: Here, mean is bit larger than the median, so we do not think that this variable has a normal…

Q: A fitness center is interested in finding a 98% confidence interval for the mean number of days per…

A: given data, CI=0.98α=1-0.98=0.02n=252μ=2.5σ=1.9we have to find out the the confidence interval for…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.