You are conducting a study to see if the proportion of voters who prefer Candidate A is significantly more than 0.83. You use a significance level of a = 0.002. Ho:p = 0.83 H1:p> 0.83 You obtain a sample of size n = 356 in which there are 317 successes. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is. less than (or equal to) a greater than a This test statistic leads to a decision to... O reject the null accept the null fail to reject the null As such, the final conclusion is that. There is sufficient evidence to warrant rejection of the claim that the proportion of voters who prefer Candidate A is more than 0.83. There is not sufficient evidence to warrant rejection of the claim that the proportion of voters who prefer Candidate A is more than 0.83. O The sample data support the claim that the proportion of voters who prefer Candidate A is more than 0.83. O There is not sufficient sample evidence to support the claim that the proportion of voters who prefer Candidate A is more than 0.83.

You are conducting a study to see if the proportion of voters who prefer Candidate A is significantly more than 0.83. You use a significance level of a = 0.002. Ho:p = 0.83 H1:p> 0.83 You obtain a sample of size n = 356 in which there are 317 successes. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is. less than (or equal to) a greater than a This test statistic leads to a decision to... O reject the null accept the null fail to reject the null As such, the final conclusion is that. There is sufficient evidence to warrant rejection of the claim that the proportion of voters who prefer Candidate A is more than 0.83. There is not sufficient evidence to warrant rejection of the claim that the proportion of voters who prefer Candidate A is more than 0.83. O The sample data support the claim that the proportion of voters who prefer Candidate A is more than 0.83. O There is not sufficient sample evidence to support the claim that the proportion of voters who prefer Candidate A is more than 0.83.

Name: You are conducting a study to see if the proportion of voters who pre
Uploaded: 2024-03-20T07:07:00.000Z
Channel: Bartleby
Description: You are conducting a study to see if the proportion of voters who prefer Candidate A is significantly more than 0.83. You use a significance level ofa = 0.002.Ho:p = 0.83H1:p > 0.83You obtain a sample of size n = 356 in which there are 317 successes

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Age discrimination: the following table presents the number of employees, by age group, who were promoted, or not promoted, in a sample drawn from a certain industry during the past year.
DII Given below are the sample means for fifteen samples consisting of five data values each. Assume that the mean of the sample means is ten and the computed values for the UCL and LCL of the chart are 15 and 5, respectively. Below is the chart. Is this process in statistical control? Why or why not? Select the best answer choice. Sample 1 2 3 Mean 9 11 6 17+ 16- 15 14+ 13+ 12+ 11+ 10- 9. 8+ 7- 6 5 4. 3- 2- 1- R Submit Question $ F4 % -1 + O No, because there are eight consecutive points all above or all below the centerline. O No, because there is a point lying beyond the upper or lower control limit. O No, because there is a pattern, trend, or cycle that is obviously not random. O No, because more than one of the answer choices above are correct. O Yes, this process is within statistical control. 5 T 4 5 12 9 ▬▬ FS 6 7 8 11 7 8 6 6 Y H 49 9 10 12 16 F6 8 & 7 9 U 11 12 6 13 J 10 F7 11 13 14 15 12 11 7 8 12 PrtScn 13 FB K 15 9 UCL centerline LCL Home 16 Q F9 L ) End 0 F10 A PgUp ☎
Thanks for your help today
Using the General Social Survey of 2012, determine if there is sufficient evidence to infer that the average American watches more than 24 hours per week, which is 3 hours per day (TVHOURS). Use a 5% significance level for all tests.ONLY USE EXCEL AND PLEASE SHOW ALL STEPS AND EXCEL COMMANDS. ?0:?=3 ?1:?>3 ID AGE SEX DEGREE HRS1 WRKSLF TVHOURS 55088 22 1 3 15 2 1 55089 21 1 1 30 2 55090 42 1 1 60 2 55091 49 2 1 2 4 55092 70 2 3 2 3 55093 50 2 3 2 4 55094 35 2 2 2 3 55095 24 2 0 55096 28 2 0 55097 28 2 3 40 2 55098 55 1 0 2 6 55099 36 2 3 20 2 55100 28 2 1 55101 59 2 1 2 2 55102 52 1 0 32 2 2 55103 35 2 1 53 2 55104 36 1 1 60 2 2 55105 47 2 1 40 2 3 55106 55 1 1 40 2 55107 18 2 1 5 55108 76 2 0 2 55109 39 1 0 12 2 55110 54 1 2 40 2 3 55111 45 2 2 40 2 0 55112 71 1 1 2 2 55113 42 2 3 75 2 55114 22 1 1 40 2 2 55115 50 1 0 8 55116 81 2 3 2 4 55117 44 2 1…
A null hypothesis states that p=.7, the observed sample proportion is p=.653 with a sample size of n=90. Determine the z-score. -0.97 O 0.92 -1.48 O 1.35
A basketball player wants to know if they make more than 75% of the penalty shots that they take. What is the appropriate test statistic for this scenario? one sample t-test two independent samples t-test two related samples t-test ANOVA
Q3.3 Normal, but why? A meal package for use at the space station is to be prepared by combining three separate components: protein, fruit/vegetable, and grains. Each of the components is to be randomly selected. Summary values for the caloric content for each of the components are given in the table. Component Protein (P) Fruit/vegetable (F) Grain (G) Mean (calories) 120 55 84 Stdv (calories) 6.4 Save Answer 1.0 3.6 Assume that the distributions of caloric content for each of the components are approximately normally distributed. Since the meal package consists of protein, fruit/vegetable, and grains, the total caloric content of a meal package is the random variable T, where T = P + F + G. Briefly explain why it is appropriate to say that T is approximately normally distributed. Q3.4 Probability Less than 275 Calories On your own piece of paper find the approximate probability that a randomly selected meal package will have less than 269 calories? (Draw an appropriate diagram, find a…
A person is interested in studying the amount of time (in minutes ) people spend on social media in a day. The following data is collected from a sample of 12 people : 45, 60,25,55,75,90,100,120,105,80, 0 and 220. Does the data contain outlier(s)? Explain your reasoning. ( use empirical rule and use the quartile method to check ).
An independent measures study with n = 6 in each sample produces a sample mean difference of 8 points and Sm1-m2= 2. What is the value for the T statistic? A. 1 B. 2 C. 4 D. 4/-8
help
Random digit dialing telephone surveys used to exclude cell phone numbers. If the opinions of people who have only cell phones differ from those of people who have landline service, the poll results may not represent the entire adult population. The Pew Research Center interviewed separate random samples of cell-only and landline telephone users who were less than 30 years old. Here’s what the Pew survey found about how these people describe their political party affiliation. What is the chi-square test statistic value? Round to two decimal places.