You are asked to design a horizontal curve with a 40-degree central angle (A=40) for a two-lane road with 11-ft lanes. The design speed is 70 mi/hr and superelevation is limited to 0.06 ft/ft. Give the radius, degree of curvature, and length of curve that you would recommend. Also, assume the
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- 4. Horizontal Curve: P.C. 12+00.00 P.I T 4= 30° P.T. This highway has a 60 mph speed limit requiring a minimum radius for any curve to be 1500'. If the curve is to begin at Station 12+00.00 and is to have a radius of 1610.10', how long will the curve be? At what station will the PI and PT go? How long will E be? (Answers should all be in hundredths.)An equal-tangent vertical curve connects a +3.2 % and a -1.1 % grade. The PVI is at station 100+20 and elevation 950 ft and the PVT is at station 105+20. Answer the following 5 questions Question 3 to Question 7. The station of the PVC is at: sta 93+20 sta 95+20 sta 97+20 sta 99+20 sta 105+20Given a vertical alignment connecting a -4% grade with a +2% grade with the PVC station at 34+64 with elevation 121' and its low point at station 43+88, answer to the following 4 questions. You can use K-values. 1) The design speed, in mph, of the curve is: O 50 O 60 O 65 O 75 O 80
- The design speed for a two-lane highway (lane width=12 ft.) is 60 mph. The localjurisdiction governs 8% superelevation. The central angel of the curve is 40 degrees. The PI station is at 452+50.What is the curve radius to the travel path (R)? What is the curve radius (R)? What is the curve length (L)? What isthe station of PC? What is the station of PT? What is the SSD? How many feet must be cleared from the lane'sshoulder edge to provide adequate stopping sight distance?12. Find the minimum length of curve for the following scenarios. Entry Grade Exit Grade Design Speed Reaction Time A 3% 8% 45 mi/hr 2.5 s В -4% 2% 65 mi/hr 2.5 s 0 % -3% 70 mi/hr 2.5 sA horizontal curve is being designed for a new four-lane roadway with 11-ft lanes. The PT is located at station 1050+20, the design speed is 45 mph and maximum superelevation of 4%. If the central angle of the curve is 30 degrees, what is the radius of the curve and location of the PC and PI?
- The point of intersection (Pl;) of two tangent lines is Station 1500+20. The radius (R1) of curvature is 900 feet, and the angle of deflection is 52°. • Find degree of curvature of curve1 and find the stations of PC1 and PT1 • If this curve is on a 2% grade with designed speed of 60 mph, driver reaction time of 2.5s, find the closest any roadside object can be located to the centerline of the inside edge of the pavement? • A reverse curve is designed with two curves (curve 1 and curve 2 connected with minimum tangent), if curve 2 has the same radius (R2) with curve 1, what are minimum tangent and radius R2? Find the stations of PC2, Pl2 and PT2 and angle of deflection (A2).A 5% grade intersects a -3.4% grade at station 41+990 of elevation 42.30 m. Design a vertical summit parabolic curve connecting the two tangent grades to conform with the following safe stopping sight distance specifications.Design Velocity = 60 kphHeight of driver's eye from the road pavement = 1.37 mHeight of an object over the pavement ahead = 100 mm Perception-reaction time = 3/4 sCoefficient of friction between the road and the tires = 0.15A section of a two-lane, two-way highway (2 @ 3.5 m) is to be designed with a circular curve. Sta. Pl at 200 + 100.000 Design speed = 60 kph Intersection angle = 40 degrees Rate of change of acceleration: 0.5 m/sec2
- A simple horizontal curve has 35 degrees of curvature and subtends an angle of 110 degrees. If the PC is at station 3 + 65.00 ft, what is the intermediate chord length (ft) (i.e. the straight line distance between two sequential full stations)? Response Feedback: 8 C =2Rsin- D 2The angle between a 5-m full station of a certain curve is 10°. The curve has 7 intermediate stations between P.C. (10 + 300m) and P.T. After laying out the curve, it was found out that the P.T. falls in a property lot and it should be moved in a way that the P.T. will be free from crossing the lot. Compute all the necessary elements of the old curve and new relocated curve.Design a vertical curve connecting PVI₁ (station = 4+980, Elevation = 198 m), PVI₂ (station = 5+990, Elevation = 163 m) and PVI₃ (station = 6+400, Elevation = 140 m) for an Illuminated road with a design speed of 90 km/h. Compute road elevations at 20 m even stations, station and elevation of high point on the curve. START YOUR SOLUTION WITH A QUALITATIVE SKETCH