MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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Yoplait yogurt is made using a special mixing technique to remove excess liquid. This process yields a lighter, creamer yogurt with more sugar per serving than a regular yogurt. Suppose the amount of protein, X, in a 5.3-oz serving of Yoplait mixed berry yogurt is
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- At the distribution hub of a major grocery store chain, a large shipment of honeydew melons has arrived. A worker chooses a random sample of 8 of the melons and records their weights (in kg) as shown below. 1.5, 2.8, 2.2, 3.5, 0.9, 2.5, 4.2, 3.2 Send data to Excel (a) Graph the normal quantile plot for the data. To help get the points on this plot, enter the data into the table in the correct order for a normal quantile plot. Then select "Compute" to see the corresponding area and z-score for each data value. Send data to calculator Index Data value Area 2-score 1 2 3 4 5 6 7 $ D D Compute 田arrow_forwardSuppose that males between the ages of 40 and 49 eat on average 103.8 g of fat every day with a standard deviation of 4.02 g. The amount of fat a person eats is not normally distributed but it is relatively mound shaped. State the random variable. The amount of fat a male between the ages of 40 and 49 eats every day. The mean amount of fat males between the ages of 40 and 49 eats every day. The standard deviation of the amount of fat males between the ages of 40 and 49 eats every day. Find the probability that a sample mean amount of daily fat intake for 32 men age 40-59 is more than 100 g. Round to four decimal places. P(x > 100) = Find the probability that a sample mean amount of daily fat intake for 32 men age 40-59 in the U.S. is less than 94 g. Round to four decimal places. P(x < 94)= If you found a sample mean amount of daily fat intake for 32 men age 40-59 in the U.S. less than 94 g, what would you conclude? O If the sample mean for 32 men age 40-59 were less than 94 g, there is…arrow_forwardTwo samples with P, =.25,n, = 36 and p, = .3,n, = 49. Test if populations p, # p, at a= 0.05 level of significance. 8 %3Darrow_forward
- Titanium alloys have very high hardness. Adding small amounts of copper tends to improve their properties, such as hardness. In order to evaluate the effect of copper addition on hardness of titanium alloys, 10 random casts with 5% copper were made in an argon-arc melting furnace. The Rockwell hardness was determined for each of the casts. Then, the casts were subjected to high temperature (HT) and hardness was determined again in the second row. Assume hardness follows a normal distribution. Use the data below to answer the next three questions. 248 246 245 251 248 250 247 246 243 244 HARD5 HARD5HT 250 247 246 251 251 253 248 246 249 247 (a) Do the data provide evidence that high temperature increases the hardness of 5% copper alloys, on average? What is the distribution of the test statistic under the null hypothesis and the exact p-value? O t-distribution with df = 18; p-value = 0.0862 O t-distribution with df = 9; p-value = 0.00712 O t-distribution with df = 9; p-value = 0.00356 O…arrow_forwardWhen a poultry farmer uses his regular feed, the newborn chickens have normally distributed weights with a mean of 62.462.4 oz. In an experiment with an enriched feed mixture, ten chickens are born with the following weights (in ounces). 66.5, 64.4, 64.6, 65.5, 66.3, 67.4, 66, 62.4, 65.9, 6266.5, 64.4, 64.6, 65.5, 66.3, 67.4, 66, 62.4, 65.9, 62 Use the α=0.01α=0.01 significance level to test the claim that the mean weight is higher with the enriched feed. (a) The sample mean is x⎯⎯⎯=x¯= (b) The sample standard deviation is s=s= (c) The test statistic is t=t= (d) The critical value is t∗=t∗= (e) The conclusion isarrow_forwardThe heights of men in a certain city are normally distributed with a mean of 275 cm and a variance of 25cm. Compute the minimum height for the top sixteen percent of the men in the city.arrow_forward
- Give a 99.8% confidence interval, for μ₁ −μ₂ given the following information. n₁ = 35, x₁ = 1 2.41, s₁ = 0.39 81 n₂ = 20, x₂ = 2.62, s₂ = 0.83 2 -0.21 ✓0.69 X Use Technology Rounded to 2 decimal places.arrow_forwardA manufacturing company produces bearings. One line of bearings is specified to be 1.64 centimeters (cm) in diameter. A major customer requires that the variance of the bearings be no more than .001 cm². The producer is required to test the bearings before they are shipped, and so the diameters of 16 bearings are measured with a precise instrument, resulting in the following values. Assume bearing diameters are normally distributed. Use the data and a = 0.01 to test to determine whether the population of these bearings is to be rejected because of too high a variance. 1.68 1.62 1.63 1.70 1.66 1.63 1.65 1.71 1.64 1.69 1.57 1.64 1.59 1.66 1.63 1.65 Appendix A Statistical Tables (Round your answer to 2 decimal places, e.g. 15.25.) The value of the test statistic is and we reject the null hypothesis ⇒arrow_forwardAccording to Zero Population Growth, the average urban U.S. resident consumes 3.3 pounds of food per day. Is this figure accurate for rural U.S. residents? Suppose 64 rural U.S. residents are identified by a random procedure and their average consumption per day is 3.60 pounds of food. Assume a population variance of 1.31 pounds of food per day. Use a 5% level of significance to determine whether the Zero Population Growth figure for urban U.S. residents also is true for rural U.S. residents on the basis of the sample data. Appendix A Statistical Tables (Round your answer to 2 decimal places, e.g. 15.75.) The value of the test statistic is z = and wearrow_forward
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