yes, hi. I've seen another source, use set variables to 0 and then solve individually, answers are usually,  x = (29/3)t y = 0 z = 29/5 - (29/5)t

Algebra for College Students
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Author:Jerome E. Kaufmann, Karen L. Schwitters
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yes, hi. I've seen another source, use set variables to 0 and then solve individually, answers are usually, 

x = (29/3)t y = 0 z = 29/5 - (29/5)t

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