y" + y' + 16y = 0. (a) Find the general solution of this differential equation. (b) Find the particular solution that satisfies the initial conditions y(0) = 3, y'(0) = 9. (c) Draw the graph of the particular solution for 0 < t < 15.

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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### Differential Equations

#### Problem Statement

Consider the second-order linear homogeneous differential equation given by:

\[ y'' + y' + 16y = 0. \]

(a) **Find the general solution of this differential equation.**

(b) **Find the particular solution that satisfies the initial conditions \( y(0) = 3 \) and \( y'(0) = 9 \).**

(c) **Draw the graph of the particular solution for \( 0 < t < 15 \).**

#### Explanation:

**(a) General Solution:**

To find the general solution of the differential equation \( y'' + y' + 16y = 0 \), we start by finding the characteristic equation. The characteristic equation is obtained by replacing \( y'' \) with \( r^2 \), \( y' \) with \( r \), and \( y \) with 1.

\[ r^2 + r + 16 = 0 \]

Solving this quadratic equation gives the roots of the characteristic equation.

**(b) Particular Solution:**

Next, we use the initial conditions \( y(0) = 3 \) and \( y'(0) = 9 \) to find the specific constants in our general solution from part (a).

**(c) Graph of the Particular Solution:**

Finally, to fully understand the solution, we can plot the particular solution for the range \( 0 < t < 15 \).

---

Graph: ***Explanation Required***

For part (c), you would draw the graph of the particular solution. The graph would typically illustrate how the solution behaves over time within the given interval \(0 < t < 15\).

---

This transcription provides a structured approach to solving the given differential equation, outlining the steps necessary for deriving both the general and particular solutions and understanding their graphical representations.
Transcribed Image Text:### Differential Equations #### Problem Statement Consider the second-order linear homogeneous differential equation given by: \[ y'' + y' + 16y = 0. \] (a) **Find the general solution of this differential equation.** (b) **Find the particular solution that satisfies the initial conditions \( y(0) = 3 \) and \( y'(0) = 9 \).** (c) **Draw the graph of the particular solution for \( 0 < t < 15 \).** #### Explanation: **(a) General Solution:** To find the general solution of the differential equation \( y'' + y' + 16y = 0 \), we start by finding the characteristic equation. The characteristic equation is obtained by replacing \( y'' \) with \( r^2 \), \( y' \) with \( r \), and \( y \) with 1. \[ r^2 + r + 16 = 0 \] Solving this quadratic equation gives the roots of the characteristic equation. **(b) Particular Solution:** Next, we use the initial conditions \( y(0) = 3 \) and \( y'(0) = 9 \) to find the specific constants in our general solution from part (a). **(c) Graph of the Particular Solution:** Finally, to fully understand the solution, we can plot the particular solution for the range \( 0 < t < 15 \). --- Graph: ***Explanation Required*** For part (c), you would draw the graph of the particular solution. The graph would typically illustrate how the solution behaves over time within the given interval \(0 < t < 15\). --- This transcription provides a structured approach to solving the given differential equation, outlining the steps necessary for deriving both the general and particular solutions and understanding their graphical representations.
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