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√³ — ( y = x²) e³ ³ d x = У 8 二記 e -Y do y²=x² У = ge²* ((y² - ≤3³y) (y² - 3y²-y)) =&e³·(g³- £3³ +3² + ≤3³) -y = √18 e²³. (zy³) ニキビ 3 iy³

√³ — ( y = x²) e³ ³ d x = У 8 二記 e -Y do y²=x² У = ge²* ((y² - ≤3³y) (y² - 3y²-y)) =&e³·(g³- £3³ +3² + ≤3³) -y = √18 e²³. (zy³) ニキビ 3 iy³

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter2: Equations And Inequalities
Section2.1: Equations
Problem 54E
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The answer is 1/6 * e^-y * y^3.  Please tell me which steps are wrong in my work, thank you!

√³ — ( y = x²) e³ ³ d x = У 8 二記 e -Y do y²=x² У = ge²* ((y² - ≤3³y) (y² - 3y²-y)) =&e³·(g³- £3³ +3² + ≤3³) -y = √18 e²³. (zy³) ニキビ 3 iy³
Transcribed Image Text:√³ — ( y = x²) e³ ³ d x = У 8 二記 e -Y do y²=x² У = ge²* ((y² - ≤3³y) (y² - 3y²-y)) =&e³·(g³- £3³ +3² + ≤3³) -y = √18 e²³. (zy³) ニキビ 3 iy³
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