y of radical intermediates that are formed during the radical halogenation mechanism. 6. Consider the reaction below to answer the following question(s). CH3CH=CHCH2CH2CH3 NBS hv CH3CH CHCHCH2CH₂ + Br B CH₂CHCH=CHCH2CH3 Br C A a) Place asterisks(*) at all allylic positions in compound A. ANSWER: b) Draw the resonance forms of the allylic radical intermediate that accounts for the formation of B and C ANSWER: c) D and E, below, are minor products in this reaction Explain why BrCH2CH=CHCH2CH2CH3 + D ANSWER: Learning objective CH2=CHCHCH2CH2CH3 Br E

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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y of radical intermediates that are formed during the radical halogenation mechanism.
6. Consider the reaction below to answer the following question(s).
CH3CH=CHCH2CH2CH3
NBS
hv
CH3CH CHCHCH2CH₂
+
Br
B
CH₂CHCH=CHCH2CH3
Br
C
A
a) Place asterisks(*) at all allylic positions in compound A.
ANSWER:
b) Draw the resonance forms of the allylic radical intermediate that accounts for the formation of B and C
ANSWER:
c) D and E, below, are minor products in this reaction Explain why
BrCH2CH=CHCH2CH2CH3 +
D
ANSWER:
Learning objective
CH2=CHCHCH2CH2CH3
Br
E
Transcribed Image Text:y of radical intermediates that are formed during the radical halogenation mechanism. 6. Consider the reaction below to answer the following question(s). CH3CH=CHCH2CH2CH3 NBS hv CH3CH CHCHCH2CH₂ + Br B CH₂CHCH=CHCH2CH3 Br C A a) Place asterisks(*) at all allylic positions in compound A. ANSWER: b) Draw the resonance forms of the allylic radical intermediate that accounts for the formation of B and C ANSWER: c) D and E, below, are minor products in this reaction Explain why BrCH2CH=CHCH2CH2CH3 + D ANSWER: Learning objective CH2=CHCHCH2CH2CH3 Br E
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