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Goerge conducted a study in which some mice. Were operated to produce a heart lesion .other mice underwent a sham operation that left indistinguishable scars but did no damage to the actual heart tissue.Suppose that 8mice were sent to each of the 5 experiments, with the experimenters chosen randomly. In each shipment, there were 2 lesions mice labeled as lesions, 2 non lesioned mice labeled as lesions ,2 lesuoned mice labeled as non lesioned ,and 2 non lesioned mice labeled as non lesioned .
The experimenters reported back the number of trials required by each mouse to learn a T maze based discrimination problem
1 identify the factors in the study. Should mouse be regarded as a factor
2 which factor should be regarded as fixed, and which as random
3 are any factors nested in others?
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- Rhianna hears that watching ASMR videos on YouTube can help with insomnia. She conducts a sleep study on 60 people who have difficulty sleeping by asking a simple random sample of 30 participants to watch at least 20 minutes of ASMR videos prior to sleeping and the remaining 30 participants to attempt to sleep without watching any videos. During the study, the subjects are connected to an EEG machine, which is used to measure brain activity. Rhianna analyzes the EEG results and concludes that those who watched the ASMR videos experienced a better quality of sleep than those who did not. i. Identify the treatments in Rhianna’s study. For i., the treatments are what the participants do that will impact their sleep. A. being connected to an EEG machine B. experiencing difficulty sleeping C. watching at least 20 minutes of ASMR videos D. watching at least 20 minutes of non-ASMR videos E. watching no videos prior to sleep F. all of the above G. Options A & B H.…arrow_forwardAn agriculturalist on a farm conducted a study to investigate whether ladybugs are effective in reducing damagecause by moths to the fruit of avocado trees. The agriculturalist randomly sampled 66 avocado trees from the farmand paired them based on size. One tree from each pair was randomly assigned to a greenhouse with ladybugs, andthe other tree in the pair was assigned to a green house without ladybugs. After one month, the number of damagedavocado fruit on each tree was recorded. All other variables were held constant over the one-month period. Thedifference in the number of damaged avocado fruit per tree pair (without ladybugs minus with ladybugs) wascalculated for each of the 33 pairs and is shown in the stem plot below. Difference in Number of Damaged Avocado Fruit Per Avocado Tree Pair-3 0 5 8 9-2 3 7 7 8-1 1 3 4-0 90 0 0 5 8 91 0 2 7 92 6 63 2 2 4 44 2 3 4 55 0 2 Key: = 52 Damaged Avocado Fruit a) Explain what a positive difference indicates in the context of the study. b)…arrow_forwardAn antidepressant has historically been known to relieve depression for 65% of patients who use the drug. The drug's formula was changed recently to include smaller dose of its main, active ingredient. Due to this change, a medical researcher suspects that among all people with depression who use the new version of the drug, the proportion, p, of people who find relief is lower than 65%. A random sample of 240 patients who use the new version is selected by the researcher, and 149 of them find relief from depression. Based on these data, can we support the researcher's claim at the 0.05 level of significance? Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places and round your answers as specified in the table. (If necessary, consult a list of formulas.) (a) State the null hypothesis H and the alternative hypothesis H,. Ho :0 H¡ :0 (b) Determine the type of test statistic to use. (Choose one) ▼ OSO (c) Find the…arrow_forward
- A colon cancer screening study is being conducted in Nottingham, England. Individuals 50 to 75 years old will be screened with the Hemoccult test. In this test, a stool sample is tested for the presence of blood. If the Hemoccult test result is negative, no further testing is done. If the Hemoccult test result is positive, the individual will have a second stool sample tested with the Hemoccult II test. If this second sample also tests positive for blood, the individual will be referred for more extensive evaluation. What is the effect on net sensitivity and net specificity of this method of screening? Net sensitivity is decreased and net specificity is increased Net sensitivity and net specificity are both increased Net sensitivity remains the same and net specificity is increased Net sensitivity is increased and net specificity is decreased. The effect on net sensitivity and net specificity cannot be determined from the dataarrow_forwardA sleep therapist wanted to see if a herbal tea advertised as a sleep aid really worked. He located 46 people with sleep problems and matched them into pairs on the basis of sleep problems and suggestibility. He then randomly assigned one person from each pair to drink the tea at bedtime (the experimental group), while the control group went to sleep as they normally did. He used an EEG to measure the minutes to sleep onset (the fewer the minutes to sleep onset, the better). He found MControl = 21.20, MExperimental = 19.70, sD = 5.47. Use an alpha of .05 and a two-tailed test to determine if the herbal teach was effective.arrow_forwardthe brand name of a certain chain of coffee shops has a 6% recognition rate in the town of Coffleton. An executive from the company wants to verify the recognition rate as the company is interested in opening a coffee shop in the town. he selects a random sample of 6 Coffleton residents, find the probabilty that the number that recognize the brand name is not 4arrow_forward
- An antidepressant has historically been known to relieve depression for 80% of patients who use the drug. The drug's formula was changed recently to include a smaller dose of its main, active ingredient. Due to this change, a medical researcher suspects that among all people with depression who use the new version of the drug, the proportion, p, of people who find relief is lower than 80%. A random sample of 215 patients who use the new version is selected by the researcher, and 159 of them find relief from depression. Based on these data, can we support the researcher's claim at the 0.05 level of significance? Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places and round your answers as specified in the table. (If necessary, consult a list of formulas.) (a) State the null hypothesis H and the alternative hypothesis H₁. H:0 H₁ :0 (b) Determine the type of test statistic to use. (Choose one) ▼ (c) Find the value…arrow_forwardTwo different blood pressure medicines are being compared to determine if the average reduction in blood pressure is the same for each medication. The goal of the study is to determine if the medications differ. Twenty men age 50-60 years old are selected for the study. Ten men are chosen at random to receive the first medication and the other 10 men receive the second medication. Each of the 20 men is monitored for one month to determine the change in blood pressure over that time. Minitab provides the 95% confidence interval for (mu1 - mu2) (2.63, 14.18) a. Interpret this 95% CI. b. What assumptions (be specific) are necessary to construct this CI?arrow_forwardTrematodes of the species Euhaplorchis californiensis may infect the California kill fish, Fundulus parvipinnis. Researchers have observed that infected fish spend excessive time near the water surface, where they may be more vulnerable to bird predation. Researchers set up an experiment in a large outdoor tank that stocked with three kinds of killifish, uninfected, lightly infected, and highly infected, and recorded the number of fish that is eaten by birds. State the null and alternative hypothesisarrow_forward
- A doctor released the results of clinical trials for a vaccine to prevent a particular disease. In these clinical trials, 400,000 children were randomly divided in two groups. The subjects in group 1 (the experimental group) were given the vaccine, while the subjects in group 2 (the control group) were given a placebo. Of the 200,000 children in the experimental group, 41 developed the disease. Of the 200,000 children in the control group, 109 developed the disease. Complete parts (a) through (f) below. (d) What is a placebo? OA. An innocuous medication OB. Whatever does the opposite of the actual medication OC. A pill OD. Water (e) Why is such a large number of subjects needed for this study? OA. The number of subjects is so large because the vaccine is very effective. OB. The number of subjects is so large because a large sample size is needed to ensure that the samples are independent. OC. The number of subjects is so large because these are clinical trials, which require a…arrow_forwardBonnie and her friends are dubious that a new abdominal exercise machine is as effective as its commercial claims. They decide to conduct an experiment to find out. For three months, Bonnie has 25 randomly chosen friends use the new machine, and 25 others do traditional abdominal exercises. At the end of the experiment, she counts the number of sit-ups each friend can do in one minute. No. of sit-ups for friends who use machine 43 29 41 22 43 28 35 26 31 48 41 24 48 25 23 35 25 28 28 31 27 45 41 22 46 Mean: 33.4 sit-ups No. of sit-ups for friends who do traditional exercises 44 33 33 24 49 39 21 45 44 48 47 50 43 46 29 46 45 32 36 41 49 45 28 49 29 Mean: 39.8 sit-ups How much lower is the average for the treatment group than the average for the control group? sit-upsarrow_forwardMany golfers wear wrist bracelets containing magnets because they claim the magnets improve balance and the length of shots played off the tee. A golfer would like to determine if the claim has merit and finds 200 volunteers who play golf to participate in an experiment. Half of the golfers are randomly assigned to wear a bracelet with magnets, while the other half wear a bracelet without magnets. Each golfer plays normally for a month, after which the length of their shots in a subsequent round is recorded. What is the response variable in this experiment? the age of each golfer the 200 volunteers the length of shots played by the golfers whether the golfers wear or do not wear the braceletarrow_forward
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