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x[n] ylo) y[n] = ½ ( x[n] + 2x[n-1]-y[n-1]) We can't be sure this way, but it does look stable (and it turns out it is). 1 2 4 x[n]= 8[n] 2x[n-1] - y[n-1] -0.75 0.375 -0.1875 0.75 -0.375 0.1875 -0.09375 h[n]= % ( x[n] + 2x[n-1] - y[n-1]) 2.

x[n] ylo) y[n] = ½ ( x[n] + 2x[n-1]-y[n-1]) We can't be sure this way, but it does look stable (and it turns out it is). 1 2 4 x[n]= 8[n] 2x[n-1] - y[n-1] -0.75 0.375 -0.1875 0.75 -0.375 0.1875 -0.09375 h[n]= % ( x[n] + 2x[n-1] - y[n-1]) 2.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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D3. Please explain logic behind -y[n-1] values
x[n] yta) y[n] = ½ ( x[n] + 2x[n-1] –y[n-1]) Σ We can't be sure this way, but it does look stable (and it turns out it is). 1 2 x[n]= 8[n] 1 2x[n-1] - y[n-1] -2 -0.75 0.375 -0.1875 h[n]= % ( x[n] + 2x[n-1] - y[n-1]) 1/2 0.75 -0.375 0.1875 -0.09375 2.
Transcribed Image Text:x[n] yta) y[n] = ½ ( x[n] + 2x[n-1] –y[n-1]) Σ We can't be sure this way, but it does look stable (and it turns out it is). 1 2 x[n]= 8[n] 1 2x[n-1] - y[n-1] -2 -0.75 0.375 -0.1875 h[n]= % ( x[n] + 2x[n-1] - y[n-1]) 1/2 0.75 -0.375 0.1875 -0.09375 2.
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