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XA 0.0 mol -TA m³.sec 1 m³.sec -TA mol FAO (m³-sec) -TA mol 0.49 0.1 0.41 0.2 0.34 0.4 0.199 Reaction AB 0.6 Feed Flow Rate = 0.8- 0.117 mol sec PureA T = 500K & P = 830 kPa (8.2 atm) 0.7 0.083 0.8 0.054

XA 0.0 mol -TA m³.sec 1 m³.sec -TA mol FAO (m³-sec) -TA mol 0.49 0.1 0.41 0.2 0.34 0.4 0.199 Reaction AB 0.6 Feed Flow Rate = 0.8- 0.117 mol sec PureA T = 500K & P = 830 kPa (8.2 atm) 0.7 0.083 0.8 0.054

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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(E) Fortwo CSTRS in parallel where each CSTR is 1.6 m^3, determine the conversion after the reactors. FAO is divided equally between the two CSTRs.
Transcribed Image Text:(E) Fortwo CSTRS in parallel where each CSTR is 1.6 m^3, determine the conversion after the reactors. FAO is divided equally between the two CSTRs.
XA 0.0 mol -TA ³-sec 1 (m³-sec) -TA mol FAO (m³-sec -TA mol 0.49 0.1 0.41 0.2 0.34 0.4 0.199 Reaction A → B 0.6 0.117 mol sec PureA T = 500K & P = 830 kPa (8.2 atm) Feed Flow Rate = 0.8 0.7 0.083 0.8 0.054
Transcribed Image Text:XA 0.0 mol -TA ³-sec 1 (m³-sec) -TA mol FAO (m³-sec -TA mol 0.49 0.1 0.41 0.2 0.34 0.4 0.199 Reaction A → B 0.6 0.117 mol sec PureA T = 500K & P = 830 kPa (8.2 atm) Feed Flow Rate = 0.8 0.7 0.083 0.8 0.054
Expert Solution
Step 1: Conversion in two CSTRs in parallel

Given, feed flow rate

 F subscript A 0 space end subscript equals space 0.8 space fraction numerator m o l over denominator s e c end fraction

Tabulating data of XA and fraction numerator F subscript A 0 end subscript over denominator negative r subscript A end fraction

XAfraction numerator F subscript A 0 end subscript over denominator negative r subscript A end fraction
X subscript A space open parentheses fraction numerator F subscript A 0 end subscript over denominator negative r subscript A end fraction close parentheses subscript X subscript A end subscript
01.6326530
0.11.951220.195122
0.22.3529410.470588
0.44.0201011.60804
0.66.8376074.102564
0.79.6385546.746988
0.814.8148111.85185

Two CSTRs in parallel, each with a volume of 1.6 m3 yields same conversion as single CSTR with a volume of 3.2 m3.

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