x+5 What is the domain of ƒ(x)= x² - 6x+8

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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**Text:**

What is the domain of \( f(x) = \frac{x+5}{x^2 - 6x + 8} \)?

**Explanation:**

To determine the domain of the function \( f(x) = \frac{x+5}{x^2 - 6x + 8} \), we need to consider the values of \( x \) for which the function is defined. This function is a rational function, and it is undefined when the denominator is zero. 

To find these values, set the denominator equal to zero and solve for \( x \):

\[ x^2 - 6x + 8 = 0 \]

Factor the quadratic expression:

\[ (x - 2)(x - 4) = 0 \]

The solutions to this equation are \( x = 2 \) and \( x = 4 \). These are the values that make the denominator zero, so they need to be excluded from the domain.

**Domain:**

The domain of \( f(x) \) is all real numbers except \( x = 2 \) and \( x = 4 \). In interval notation, the domain is:

\( (-\infty, 2) \cup (2, 4) \cup (4, \infty) \)
Transcribed Image Text:**Text:** What is the domain of \( f(x) = \frac{x+5}{x^2 - 6x + 8} \)? **Explanation:** To determine the domain of the function \( f(x) = \frac{x+5}{x^2 - 6x + 8} \), we need to consider the values of \( x \) for which the function is defined. This function is a rational function, and it is undefined when the denominator is zero. To find these values, set the denominator equal to zero and solve for \( x \): \[ x^2 - 6x + 8 = 0 \] Factor the quadratic expression: \[ (x - 2)(x - 4) = 0 \] The solutions to this equation are \( x = 2 \) and \( x = 4 \). These are the values that make the denominator zero, so they need to be excluded from the domain. **Domain:** The domain of \( f(x) \) is all real numbers except \( x = 2 \) and \( x = 4 \). In interval notation, the domain is: \( (-\infty, 2) \cup (2, 4) \cup (4, \infty) \)
Expert Solution
Step 1: Definition

For defining domain of rational polynomial denumerator should not be zero.

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