⎪ ⎨ ⎪ ⎧x^2 − 1 , − 1 ≤ x < 0 2x , 0 < x < 1 1 , x = 1 −2x + 4 , 1 < x < 2 0 , 2 < x < 3 a) Is f continuous at x = 1? Why? b) Is f continuous from the left or right at x = −1? Explain why. c) Indicate the intervals where the function is continuous.

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A: The critical point of  f is x=c and f'c=0.

Q: How can we find the Absolute Extrema of a Continuous Function ƒ on a FiniteClosed Interval?

A: How can we find the Absolute Extrema of a Continuous Function ƒ on a Finite Closed Interval?

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A: To find the intervals of increasing and decreasing

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Q: 3. What are is the absolute maximum of f (x) = sin(x) cos(x) on the interval [0, 1]?

A: follow next step

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Q: If f(x) =- 2-cos(x) sin(x) then the absolute minimum of f on the TI 3T is: interval O 2/2-1 O 2/2+1

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A: We know that,  ddxuv =vu'-uv'v2 Where u'=dudx and  v'=dvdx

Q: x² – 16 f (x) = x( x 2(х — 1)°(х — 2) : о 1)8 (x – 2) : 0 - -

A: If the given function is equal at LHL and RHL at x=3 then the given function is continuous at x

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Q: and the domain of the function using interval notation. To enter ∞o, type infinity. To enter U, type…

A: We can solve this as follows:

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Q: (b). Find the bound for absolute error at x = 2.9 on the interval [x, x,], where x, = 2.25, x, =…

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A: Given that f'x &lt;2 for all x≥2 and f2=7.We need to show that f4&lt;11.

Q: 1. If f:(0, 3) → R is continuous, must its range be an open (possibly infinite) interval?

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Q: 3. What are is the absolute maximum of f (x) = sin(x) cos(x) on the interval [0, ¤]?

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