x1 = Solve the following system of linear equations: x2 = How to enter the solution: • If the value of a variable is a number, just enter the number. • If the value of a variable is a formula involving free variables, enter the formula. For example, if you obtain that z₁ = 1-2x2 + 3x3 where 2 and 3 are free, then as the value of a you should enter 1 2*x 2 + 3*x 3. Use the underscore to indicate subscripts of variables, and to indicate multiplication. • If a variable is a free variable, enter the variable name as its value. For example, if x₂ is a free variable, then you should enter x 2 as the value of ₂- . If the system has no solutions enter None as the value of one of the variables. In such case you can leave values of the remaining variables blank. I -122-5-x-2 -21 +2₂-23 = 3 -321 +4x2+3+4=10 4x16x2 - 4x32x4 = -14 x3 = X4=
x1 = Solve the following system of linear equations: x2 = How to enter the solution: • If the value of a variable is a number, just enter the number. • If the value of a variable is a formula involving free variables, enter the formula. For example, if you obtain that z₁ = 1-2x2 + 3x3 where 2 and 3 are free, then as the value of a you should enter 1 2*x 2 + 3*x 3. Use the underscore to indicate subscripts of variables, and to indicate multiplication. • If a variable is a free variable, enter the variable name as its value. For example, if x₂ is a free variable, then you should enter x 2 as the value of ₂- . If the system has no solutions enter None as the value of one of the variables. In such case you can leave values of the remaining variables blank. I -122-5-x-2 -21 +2₂-23 = 3 -321 +4x2+3+4=10 4x16x2 - 4x32x4 = -14 x3 = X4=
Big Ideas Math A Bridge To Success Algebra 1: Student Edition 2015
1st Edition
ISBN:9781680331141
Author:HOUGHTON MIFFLIN HARCOURT
Publisher:HOUGHTON MIFFLIN HARCOURT
Chapter5: Solving Systems Of Linear Equations
Section5.4: Solving Special Systems Of Linear Equations
Problem 15Q
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