X = Find the vector equation for the line of intersection of the planes x - 5y + 5z = −5 and x + 5z = 1 -25 +

Find the vector equation for the line of 5x + 3y - 2z = −1 and 5x + 5z = -4 intersection of the planes r = = 0,0) + t(15,00)

Give the vector equation of the line passing through P and Q. P= (3, 1), Q = (2, 0) X = + t

Write the vector equation of the line through (9,-1) and perpendicular to (x,y) = (1,-2) + t(6,-7)

Which equations below represent the line in R³ that passes through the point (-3,5,-5) and is parallel to the vector 3i + 4j + 6k? You may select more than one equation. Or(t): +t OF(t) = + t Ox=3+3t; y = 5 + 4t; z = = 5 + 6t - OF(t): = -3, 5, -5> +t OF(t) = +t 1 - x=3+ 6t; y = 5 + 8t; z = 5+ 6t OF(t)= +t OF(t)= + t -

Find the scalar equation of the line through (3,-2) and perpendicular to the line r = (4,-3) + t(-5,1) .  Please answer.  Thank you

A line contains the points P=(−6,−2,−3)P=(-6,-2,-3) and Q=(−4,−3,−6)Q=(-4,-3,-6). A vector equation of this line is →x=−−→OP+t−−→PQx→=OP→+tPQ→, where OO is the origin.If t=2t=2, what point does this give us from the equation?