X + 12x + 35 x + 12x +35 Next Question Explain why lim lim (x + 7), and then evaluate lim x+5 x+5 x-5 x--5 x-5 Choose the correct answer below. A. Since each limit approaches - 5, it follows that the limits are equal. OB. x2. +12x+35 The numerator of the expression simplifies to x+7 for all x, so the limits are equal. X+5 C. The limits lim x2 + 12x + 35 and lim (x+7) equal the same number when evaluated using direct substitution. x+5 X-5 x-5 O D. Since x2 + 12x + 35 =x+7 whenever x# -5, it follows that the two expressions evaluate to the same number as x approaches -5 x+5 Now evaluate the limit. x+ 12x + 35 lim x+5 (Simplify your answer.) X-5

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
x
Explain why lim
+ 12x +35
lim (x +7), and then evaluate lim
+12x +35
Next Question
x+5
x+5
X -5
x-5
X-5
Choose the correct answer below.
A. Since each limit approaches -5, it follows that the limits are equal.
O B.
The numerator of the expression
x + 12x + 35
simplifies to x+7 for all x, so the limits are equal.
X+5
OC.
The limits lim
x2 + 12x+35
and
lim (x+7) equal the same number when evaluated using direct substitution.
x+5
X-5
X -5
OD.
x2 + 12x +35
Since
= x +7 whenever x# - 5, it follows that the two expressions evaluate to the same number as x approaches -5
x+5
Now evaluate the limit.
x + 12x +35
lim
(Simplify your answer.)
X+5
X-5
Transcribed Image Text:x Explain why lim + 12x +35 lim (x +7), and then evaluate lim +12x +35 Next Question x+5 x+5 X -5 x-5 X-5 Choose the correct answer below. A. Since each limit approaches -5, it follows that the limits are equal. O B. The numerator of the expression x + 12x + 35 simplifies to x+7 for all x, so the limits are equal. X+5 OC. The limits lim x2 + 12x+35 and lim (x+7) equal the same number when evaluated using direct substitution. x+5 X-5 X -5 OD. x2 + 12x +35 Since = x +7 whenever x# - 5, it follows that the two expressions evaluate to the same number as x approaches -5 x+5 Now evaluate the limit. x + 12x +35 lim (Simplify your answer.) X+5 X-5
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