Database System Concepts
Database System Concepts
7th Edition
ISBN: 9780078022159
Author: Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher: McGraw-Hill Education
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Please do number 1 using C language 

1
1. write a program using an array to perform the sum and average for the zig zag elements shown in
the above figure.
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Transcribed Image Text:1 1. write a program using an array to perform the sum and average for the zig zag elements shown in the above figure.
Expert Solution
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Step 1

List of variables used:

  • Considering an array "arr" of rows: 3 and columns: 5.
  • Variables i,j,k for looping purpose.
  • Array sum[2]: to store the sum of given figures zigzag elements.
  • Array avg[2]: to store the average of zigzag elements given figures.
  • Array count[2]: To count the number of elements in zigzag

Finding and calculating sum and average of first zigzag elements:

  • variables i and j are used for accessing elements in the array.
    • Where i represents the row.
    • where j represents the column.
  • Initialize i=0, j=0 means accessing first-row first-element.
  • Loop for accessing rows begins with termination condition i<3
    • Loop for accessing columns begins with termination condition j<=(i+1)
      •  Adding arr[i][j] to sum[0].
        • sum[0] += arr[i][j]
      • Increase count value by 1.
        • count[0]++
      • Increase j value by 1.
      • If the termination condition j<=(i+1) satisfies, exit from the loop. Otherwise, repeat the loop. 
    • Increase value of i by 1.
    • If the termination condition i<3 satisfies, exit from the loop. Otherwise, repeat the loop. 
  • Calculating average of zigzag elemnts.
    • avg[0]=sum[0]/count[0]

Finding and calculating sum and average of second zigzag elements:

  • variables i and j are used for accessing elements in the array.
    • Where i represents the row.
    • where j represents the column.
  • Initialize i=0, j=0 and k=4. 
  • Loop for accessing rows begins with termination condition i<3
    • Loop for accessing columns begins with termination condition j<5
      • if value of i equals to j ( j == i) then 
        •  Adding arr[i][j] to sum[1].
          • sum[1] += arr[i][j]
        • Increase count value by 1.
          • count[1]++
      • if value of k equals to j ( j == k) and value of i not equals to j (j != i) then 
        •  Adding arr[i][j] to sum[1].
          • sum[1] += arr[i][j]
        • Increase count value by 1.
          • count[1]++
      • Increase j value by 1.
      • If the termination condition j<5 satisfies, exit from the loop. Otherwise, repeat the loop. 
    • Increase value of i by 1.
    • decrement value of k by 1.
    • If the termination condition i<3 satisfies, exit from the loop. Otherwise, repeat the loop. 
  • Calculating average of zigzag elemnts.
    • avg[1]=sum[1]/count[1]
Step 2

CODE:

#include <stdio.h>
int main()
{
    // Declaring variables for array, sum, average and looping.
    int arr[3][5], sum[2] = {0};
    float avg[2] = {0};
    int i, j, k, count[2] = {0};
    //Reading array elements
    printf("Enter Array element of size 3 * 5:");
    for (i = 0; i < 3; i++)
    {
        printf("\nEnter %d row 5 elements:\n", i + 1);
        for (j = 0; j < 5; j++)
        {

            scanf("%d", &arr[i][j]);
        }
    }
    //Displaying Array elements
    printf("\nArray elements:");
    for (i = 0; i < 3; i++)
    {
        printf("\n");
        for (j = 0; j < 5; j++)
        {

            printf("%d\t", arr[i][j]);
        }
    }
    // calculating sum and average of first zigzag elements
    //Displatying First set of zigzag elements
    printf("\nFirst zigzag puzzle:");
    for (i = 0; i < 3; i++)
    {
        printf("\n");
        for (j = 0; j <= (i + 1); j++)
        {
            printf("%d\t", arr[i][j]);
            sum[0] += arr[i][j];
            count[0]++;
        }
    }
    avg[0] = (float)sum[0] / count[0];

    // calculating sum and average of second zigzag elements
    //Displatying second set of zigzag elements
    printf("\nSecond zigzag puzzle:");

    for (i = 0, k = 4; i < 3; i++, k--)
    {
        printf("\n");
        for (j = 0; j < 5; j++)
        {

            if (j == i)
            {
                printf("%d", arr[i][j]);
                sum[1] += arr[i][j];
                count[1]++;
            }
            if (j == k && i != j)
            {
                printf("%d", arr[i][j]);
                sum[1] += arr[i][j];
                count[1]++;
            }
            printf(" \t");
        }
    }
    avg[1] = (float)sum[1] / count[1];
    //Dsipalying sum and averages of both first and second set of zigzag elements.
    printf("\nFirst zigzag puzzle:");
    printf("\n\tSum : %d", sum[0]);
    printf("\n\tAverage : %f", avg[0]);
    printf("\nSecond zigzag puzzle:");
    printf("\n\tSum : %d", sum[1]);
    printf("\n\tAverage : %f", avg[1]);
}
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