Write regular expression for: Σ = {a,b} L = {all words that can be of any length and only have one letter b in them} Using + as ONE or more occurences Using * as ZERO or more occurences Using () for grouping
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Write regular expression for:
Σ = {a,b} L = {all words that can be of any length and only have one letter b in them}
Using + as ONE or more occurences
Using * as ZERO or more occurences
Using () for grouping
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- Q3: Superheroes Supervillains are tired of Toronto condo rental prices, so they are leaving Toronto for Mississauga. Luckily, we have valiant superheroes that can deal with them. The superhero () has a name , an intelligence score , and a strength score .ni-th0 = gin[x] + s[x] Detective Zingaro has asked for your help. For each of the supervillains, tell him the name of the superhero that should deal with that supervillain. Note: A superhero can be assigned to multiple supervillains (or none at all). Note: whenever there are multiple superheroes that satisfy the given requirements for a supervillain, report the one whose name is lexicographically smallest (i.e. the one that’s the smallest according to Python’s ordering of strings). It’s guaranteed that superheroes have distinct names. Hint: Tuples of multiple elements may be helpful here. In python, you can compare two tuples and . If and are different, the result is the same as comparing and . If and are equal, the result is the same…نقطة واحدة Let A = {a; b; c; d} and R= {(a; a); (b; c); (c; b); (d; d)} then R is Transitive Equivalent not transitiveRegular expression to NFA to DFA conversion: Describes the process of taking a unique regular expression, converting that regular expression to an NFA, then converting the NFA into a DFA. Your regular expression must have at minimum two union, two concatenation, and two Kleene star operations. As followed, concatenations of single charaters can be condensed. Your regular expression cannot be a solved problem from any book. You should describe the regular expression with both processes to convert the regular expression to an NFA and the conversion of that NFA into a DFA.
- Matrix Problem Code this in C Write a program that reads two matrices of integers. It then generates the sum, difference, and product of the two matrices. The sum of the two matrices of the same size is a matrix with elements that are the sums of the corresponding elements of the two given matrices. Addition is not defined for matrices of different sizes. If A and B are matrices of the same size, then we define subtraction as follows: A – B = A + (-B). Thus, to subtract matrix B from matrix A, we simply subtract corresponding elements. To multiply a matrix by another matrix we need to do the "dot product" of rows and columns. The "Dot Product" is where we multiply matching members, then sum up: (1, 2, 3) • (7, 9, 11) = 1×7 + 2×9 + 3×11 = 58 We match the 1st members (1 and 7), multiply them, likewise for the 2nd members (2 and 9) and the 3rd members (3 and 11), and finally sum them up. Use the following definitions:#define ROW 6#define COL 6void add(int matrixResult[][COL],int…2- Let a = [123; 2 3 4; 12 5], b = [ 2133 points ; 50 -2; 2 3 -1] prod = a* b. What is the value of prod?] ] has_perfect You are to write a function has "perfect (graph)" that takes in a BIPARTITE graph as its input, and then determintes whether or not the graph has a perfect matching. In other words, it will return the Boolean value True if it has one, and False if it does not. After compiling the above cell, you should be able to compile the following cell and obtain the desired outputs. print (has perfect({"A" : ["B", "C"], "B" : ["A", "D"], "C" : ["A", "D"], "D" : ["B", "C"]}), has perfect ( {"A" : ["B"], "B" : ["A", "D", "E"], "C" : ["E"], "D":["B"], "E": ["B","C","F"], "F":["E"]})) This should return True False Python Python
- int sum = 0; for (int i 0; i < 5; i++){ sum += i; } cout << sum;] ] is_proper You are to write a function is_proper(graph,color) that has two inputs: one a graph, and the other a labelling of the vertices, and determines whether or not the labelling is a proper vertex-coloring of the given graph. In other words, return the Boolean value True if it is, and False if it is not. After compiling the above cell, you should be able to compile the following cell and obtain the desired outputs. print (is_proper({"A": ["B", "C"], "B": ["A", "C"], "C": ["A", "B"]}, {"A": 1, "B": 2, "C": 3}), is_proper({"A": ["B", "C"], "B": ["A", "C"], "C": ["A", "B"]}, {"A": 1, "B": 1, "C": 3})) This should return True False Python Pythonc++ coding language I need help with part B and C please. If you are unable to do both, then PLEASE prioritize part C. I am really stuck and really can use the help. This is the code for c that was provided in order to guide me: const int N =31; // N parking spaces bool parking[N]; // the garage void EmptyTheLot(bool parking[], int N) { for(int i=0; i<N; i++) p[i]=false; // empty space } // returns -1 if no space found, //otherwise it returns 0<=i<N for a valid space. int FindSpace(int PlateNumber, bool parking[], int N) { // ????? } main() { EmptyTheLot(parking, N); // start with an empty parking garage. // get plate numbers and fill lot. }
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